You want to find
P(1000 < X < 3000)
where X is normally distributed with mean 1751 and standard deviation 421. Transform X to Z, so that it follows the standard normal distribution with mean 0 and standard deviation 1 using the relation
X = 1751 + 421Z ==> Z = (X - 1751)/421
Then
P(1000 < X < 3000) = P((1000 - 1751)/421 < (X - 1751)/421 < (3000 - 1751)/421)
… ≈ P(-1.783 < Z < 2.967)
… ≈ P(Z < 2.967) - P(Z < -1.783)
… ≈ 0.9985 - 0.0373
… ≈ 0.9612
so that approximately 96.1% of the students fall in this income range.
Answer:
0.8989
Step-by-step explanation:
Using the Newton's Raphson approximation formula.
Xn+1 = Xn - f(Xn)/f'(Xn)
Given f(x) = x³-2x+2
f'(x) = 3x²-2
If the initial value X1 = 2
X2 = X1 - f(X1)/f'(X1)
X2 = 2 - f(2)/f'(2)
f(2) = 2³-2(2)+2
f(2) = 8-4+2
f(2) = 6
f'(2) = 3(2)²-2
f'(2) = 10
X2 = 2- 6/10
X2 = 14/10
X2 = 1.4
X3 = X2 - f(X2)/f'(X2)
X3 = 1.4 - f(1.4)/f'(1.4)
f(1.4) = 1.4³-2(1.4)+2
f(1.4) = 2.744-2.8+2
f(1.4) = 1.944
f'(1.4) = 3(1.4)²-2
f'(1.4) = 3.880
X3 = 1.4- 1.944/3.880
X3 = 1.4 - 0.5010
X3 = 0.8989
Hence the value of X3 is 0.8989
Answer:
Step 3 i think because 10-7+7=13 because if u do that problem u actually get 10 instead of 13
Step-by-step explanation:
because 10-7+7=13 because if u do that problem u actually get 10 instead of 13
Answer:
The answer is below
Step-by-step explanation:
Two triangles are said to be similar if their corresponding angles are equal and the corresponding sides are in proportion.
The distance between two points on the coordinate plane is given as:

In triangle STU:

|QR| / |TU| = 4/2 = 2
|PR| / |SU| = 6/3 = 2
|PQ| / |ST| = 2√13 / √13 = 2
Hence:
|QR| / |TU| = |PR| / |SU| = |PQ| / |ST|
Therefore, △PQR and △STU are similar triangles since the ratio of their sides are in the same proportion.
62 multiplied by 3 is 186
Add on 31 for the half hour
and you get 217