Answer: a2 + 152 = 362
Step-by-step explanation:
Thet contradict each other, that's why both of them are incorrect.
<span>Suppose that a polynomial has four roots: s, t, u, and v. If the polynomial were evaluated at any of these values, it would have to be zero. Therefore, the polynomial can be written in this form.
p(x)(x - s)(x - t)(x - u)(x - v), where p(x) is some non-zero polynomial
This polynomial has a degree of at least 4. It therefore cannot be cubic.
Now prove Kelsey correct. We have already proved that there can be no more than three roots. To prove that a cubic polynomial with three roots is possible, all we have to do is offer a single example of that. This one will do.
(x - 1)(x - 2)(x - 3)
This is a cubic polynomial with three roots, and four or more roots are not possible for a cubic polynomial. Kelsey is correct.
Incidentally, if this is a roller coaster we are discussing, then a cubic polynomial is not such a good idea, either for a vertical curve or a horizontal curve. I hope this helps</span><span>
</span>
Answer:
Below.
Step-by-step explanation:
I'll do number 20, 21, 22 for you.
20. It is ±1, ±2, ±4, ±8.
21. Reflected over the x-axis and down 4.
22. Common ratio = 25/5 = 5.
23. Imaginary roots occur in pairs so there is also a root -5i.
The answer is c.
19. Option (a).
This is a translation of 4 to the left ( due to the (x + 4).
Answer:
17
Step-by-step explanation:
f(5)=3*5+2 where X is equal to 5
Answer:
Step-by-step explanation:
Let two consecutive odd numbers
x, x+2
According to condition
X(x+2) = 899
x2 +2x -899=0
X2 +31x -29x -899=0
x(x+31) -29(x+31)=0
(x+31)(x-29)=0
X=-31 or x =29
Now,
X=29
X+2= 29+2 = 31
Two consecutive odd numbers is 29 and 31
