Question

Oneta writes an algebraic a spression with 3 terms. The y-term has a coefficient of negative 3 and the x-term has a coefficient of one. The expression does not have a constant term which expression could she have written.

Answer 1

Answer:

Option a. x - y^2 - 3y

Step-by-step explanation:

The options of the questions are

a. x - y^2 - 3y

b. x - 3y + 6

c. x + 3y^2 + 3y

d. x + 3y + 7

we know that

The expression has 3 terms

The y-term has a coefficient of negative 3 and the x-term has a coefficient of one

The expression does not have a constant term

Verify each case

case a) we have x - y^2 - 3y

The expression has 3 terms ----> is ok

The y-term has a coefficient of negative 3 ---> is ok

The x-term has a coefficient of one ----> is ok

The expression does not have a constant term ----> is ok

therefore

She could have written this expression

case b) we have x - 3y + 6

The expression has 3 terms ----> is ok

The y-term has a coefficient of negative 3 ---> is ok

The x-term has a coefficient of one ----> is ok

The expression does not have a constant term ---> is not ok (the expression have a constant term of 6)

therefore

She couldn't have written this expression

case c) we have x + 3y^2 + 3y

The expression has 3 terms ----> is ok

The y-term has a coefficient of negative 3 ---> is not ok (the y-term has a coefficient of positive 3)

therefore

She couldn't have written this expression

case d) we have x + 3y + 7

The expression has 3 terms ----> is ok

The y-term has a coefficient of negative 3 ---> is not ok (the y-term has a coefficient of positive 3)

therefore

She couldn't have written this expression