Well you are raising everything in the( ) so therefor it would be (10^3-5^3)+(10÷5) 10 to the 3rd is 1000 5 to the 3rd is 125 So 1000+125=1125 Then you have (1125)+(10÷5) You then have 1125+2 1125+2=1127
This should be the answer since FH and IG can be said to be parallel and therefore we can find both alternate angles or a vertical opposite angle with one side given. We know that ΔFHJ is reduced by a factor of 2 to get ΔGIJ.
