A 90% confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is (1.1%, 3.4%
1 answer:
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Answer:
The degrees of freedom are given by:
Since is a two-sided test the p value would be:
Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example ().
Step-by-step explanation:
Data given and notation
represent the sample mean
represent the sample deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the true mean is different from 1.35 in/year, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Calculate the statistic
We can replace in formula (1) the info given like this:
P-value
The degrees of freedom are given by:
Since is a two-sided test the p value would be:
Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example ().
Answer:
Step-by-step explanation:
(2):
First let's organise the data:
33 miles ... x mph ... 4h - downstream
33 miles ... y mph ... 7h - up the stream
x = 33/4 = 8.25 mph
y = 33/7 = 4.71 mph
(3)
P(x) =
To find the amount of key rings sold when the profit is 5000$ we have to equate P(x) with 5, because in the problem the profit of the key rings is displayed in terms of thousands.
Since the number of keyrings sold has to be positive the only answer is 4 thousand key rings.