Find the inverse of the function f(x)=4x^3-7
1 answer:
Answer:
f^-1(x)=³√[(x+7)÷4]
Step-by-step explanation:
f(x)=4x^3-7
y=4x^3-7
interchange 'y' with 'x'
x=4y^3-7
make y the subject
4y^3=x+7
divide by 4 both sides
y^3=(x+7)÷4
multiply by the cube root both sides
³√(y^3)=³√[(x+7)÷4]
y=³√[(x+7)÷4]
f^-1(x)=³√[(x+7)÷4]
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