You have the following equation for the cost of renting a car for x number of miles driven:
y = 0.15x + 65
If you travel 70 miles, then, x = 70 and you obtain for the cost y:
y = 0.15(70) + 65
y = 10.5 + 65
y = 75.5
Hence, the cost of renting a car to drive 70 miles is $75.5
B
rearrange into standard form : ax² + bx + c = 0 (a≠ 0)
2x² - 3x - 2 = 0
(x - 2)(2x + 1) = 0 ( equate each factor to zero and solve for x )
x - 2 = 0 ⇒ x = 2
2x + 1 = 0 ⇒ x = - 0.5
Answer:
h² + 9h + 23
Step-by-step explanation:
Given
f(x) = x² + 3x + 5
To evaluate f(3 + h) substitute x = 3 + h into f(x), that is
f(3 + h) = (3 + h)² + 3(3 + h) + 5 ← expand (3 + h)² using FOIL
= 9 + 6h + h² + 9 + 3h + 5 ← collect like terms
= h² + 9h + 23
3(4y+17)-y=4
12y+51-y=4
11y+51=4
11y=-47
y=-47/11
x=4(-47/11)+17
x=-188/11+17
x=-1/11
hope this helps!
Convert the given mileage of the automobile from miles per gallon to kilometers per liter through the given conversion factors.
(34 miles / gallon) x (1.61 km / 1 mile) x (1 gallon / 3.79 L) = 14.44 km/L
Thus, the automobile can travel about 14.44 kilometers per liter of the gasoline.
