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fredd [130]
3 years ago
6

Question 3

Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0
1) Question 3

The system

y = 3.5x - 3.5

y = -3.5x +3.5

has one solution.

To find it, you can add the two equations:

2y = 0 => y =0

Now replace that value in any of the two original equations.

Doing it with the first of the equations:

=> 3.5x - 3.5 = 0=> 3.5x = 3.5 = x = 3.5 / 3.5 = 1

Solution (1,0)

Answer: one solution.

2) Question 4

<span>The graph of a system of equations will intersect at more than 1 point.

Some times:

For example:

y = x + 2
2y = 2x + 4
Intersects in infinite points.

y = x + 2
y = x + 3
will not intersect

y = 2x
y = x+1
will intersect at one point.

And a system with a quadratic equation and a  linear equation may drive to intersection in two points.
</span>
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Answer:

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Step-by-step explanation:

First, "boxes of two sizes" means we can assign variables:

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Now, "There are 110 boxes in all"    means    x + y = 110

Now, the pounds for each kind of box is:

    (pounds per box)*(number of boxes)

pounds for large boxes     +    pounds for small boxes      =    4200pounds

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        (45)*(x)                   +              (30)*(y)                  = 4200

Now, Solve for one of the variables in the first equation then replace (substitute) the expression for that variable in the second.  Let's solve for x:

   x = 110 - y          [from eq1]

 

    45(110-y) + 30y = 4200            [from eq2]

     4950 - 45y  + 30y= 4200         [distribute]

     4950 - 15y = 4200

      -15y = -750

         y = 50           [divide both sides by (-15)]

 

 There are 50 small boxes.

 

Put that value into either equation (now, which is easier?) to solve for x:

  x = 110 - y

  x = 110 - 50

  x = 60

 There are 60 large boxes.

Now, let's verify our solution:

 

Is   60+50= 110 ?       [eq1]

         110 = 110 ? yes!

Is  60(45) + 50(30) = 4125   ?

     2700 + 1500 = 4200 ?

       4200 = 4200 ? yes

So we have 60 large boxes and 50 small boxes.

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Answer:

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