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Licemer1 [7]
3 years ago
8

Find the value of x and y so that both proportions will be correct:

Mathematics
1 answer:
andrew11 [14]3 years ago
6 0

The values of x and y are 0.2 and 0.4 respectively.

<em><u>Explanation</u></em>

The given proportions are.....

x: 1\frac{2}{3}=y: 3\frac{1}{3} and y:1.5=0.2:0.75

From the second proportion, we will get....

y:1.5=0.2:0.75\\ \\ \frac{y}{1.5}=\frac{0.2}{0.75} \\ \\ 0.75y=0.2*1.5\\ \\ 0.75y=0.3\\ \\ y=\frac{0.3}{0.75}=0.4

Now, we will plug this y=0.4 into the first proportion. So we will get....

x: 1\frac{2}{3}=y: 3\frac{1}{3}\\ \\ x: \frac{5}{3}=0.4:\frac{10}{3} \\ \\ \frac{x}{\frac{5}{3}}= \frac{0.4}{\frac{10}{3}}\\ \\ \frac{3x}{5}=\frac{1.2}{10}\\ \\ 30x=6\\ \\ x= \frac{6}{30}=0.2

So, the values of x and y are 0.2 and 0.4 respectively.

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3 years ago
Two numbers whose sum is 29 and their difference is 15
n200080 [17]

Answer:

22 and 7

Step-by-step explanation:

Let x and y be the two numbers we are looking for:

The statement “their sum is 29” means x + y = 29

The statement “their difference is 15” means x - y = 15

we get this system:

x + y = 29 (1)

x - y = 15   (2)

Let’s solve it :

(1) + (2) ⇒ x + y + x - y = 29 + 15 ⇒ 2x = 44 ⇒ x = 44/2 = 22

Now we replace x by 22 in equation (1) :

22 + y = 29  ⇒ y = 29 - 22 = 7

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2 years ago
How does substitution help you to solve systems of equations?
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5 0
3 years ago
A person on the top of a tall building looks through his binoculars at his friend that is 300 ft away from the building on the g
kvasek [131]

Answer:

520 feets

Step-by-step explanation:

The height of the building, h can be obtuined using trigonometry ;

From the attached diagram, opposite side = 300 feets ; height, h = adjacent side

Hence,

Tan θ = opposite / Adjacent

Tan 30° = 300 / height

0.5773502 = 300 / height

Height = 300 / 0.5773502

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Height = 520 feets

5 0
3 years ago
Two customers went to a post office to buy postcards and large envelopes. Each postcard
astraxan [27]

The right answer is Option A.

Step-by-step explanation:

Let,

x be the postcards

y be the large envelops

According to given statement;

14x+5y=12   Eqn 1

10x+15y=24.80   Eqn 2

Multiplying Eqn 1 by 3;

3(14x+5y=12)\\42x+15y=36\ \ \ Eqn \ 3

Subtracting Eqn 2 from Eqn 3;

(42x+15y)-(10x+15y)=36-24.80\\42x+15y-10x-15y=11.20\\32x=11.20\\

Dividing both sides by 32

\frac{32x}{32}=\frac{11.20}{32}\\x=0.35

Putting x=0.35 in Eqn 1;

14(0.35)+5y=12\\4.90+5y=12\\5y=12-4.90\\5y=7.10

Dividing both sides by 5

\frac{5y}{5}=\frac{7.10}{5}\\y=1.42

Therefore, one large envelope costs $1.42

The right answer is Option A.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/9738996
  • brainly.com/question/10015690

#LearnwithBrainly

4 0
3 years ago
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