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Licemer1 [7]
3 years ago
8

Find the value of x and y so that both proportions will be correct:

Mathematics
1 answer:
andrew11 [14]3 years ago
6 0

The values of x and y are 0.2 and 0.4 respectively.

<em><u>Explanation</u></em>

The given proportions are.....

x: 1\frac{2}{3}=y: 3\frac{1}{3} and y:1.5=0.2:0.75

From the second proportion, we will get....

y:1.5=0.2:0.75\\ \\ \frac{y}{1.5}=\frac{0.2}{0.75} \\ \\ 0.75y=0.2*1.5\\ \\ 0.75y=0.3\\ \\ y=\frac{0.3}{0.75}=0.4

Now, we will plug this y=0.4 into the first proportion. So we will get....

x: 1\frac{2}{3}=y: 3\frac{1}{3}\\ \\ x: \frac{5}{3}=0.4:\frac{10}{3} \\ \\ \frac{x}{\frac{5}{3}}= \frac{0.4}{\frac{10}{3}}\\ \\ \frac{3x}{5}=\frac{1.2}{10}\\ \\ 30x=6\\ \\ x= \frac{6}{30}=0.2

So, the values of x and y are 0.2 and 0.4 respectively.

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A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

5 0
3 years ago
Scientist are studying a bacteria sample. The function f(x)=360(1.07)^x gives the number of bacteria in the sample at the end of
Lapatulllka [165]

Options :

A. The initial number of bacteria is 7.

B. The initial of bacteria decreases at a rate of 93% each day.

C. The number of bacteria increases at a rate of 7% each day.

D. The number of bacteria at the end of one day is 360.

Answer:

C. The number of bacteria increases at a rate of 7% each day.

Step-by-step explanation:

Given the function :

f(x)=360(1.07)^x ; Number of bacteria in sample at the end of x days :

The function above represents an exponential growth function :

With the general form ; Ab^x

Where A = initial amount ;

b = growth rate

x = time

For the function :

A = initial amount of bacteria = 360

b = growth rate = (1 + r) = 1.07

If ; (1 + r) = 1.07 ; we can solve for r to obtain the daily growth rate ;

1 + r = 1.07

r = 1.07 - 1

r = 0.07

r as a percentage ;

0.07 * 100% = 7%

7 0
2 years ago
2/5 of the members of a school band are 6th graders. What percent of
faust18 [17]

Answer:

60%

Step-by-step explanation:

3/5 is 60%

7 0
3 years ago
Read 2 more answers
HELP <br><br>Determine whether the relation is a function<br><br> y=2w=2​
nexus9112 [7]

Answer:

Hi there!

I might be able to help you!

It is NOT a function.

<u>Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function</u>. <u>X = y2 would be a sideways parabola and therefore not a function.</u> Good test for function: Vertical Line test. If a vertical line passes through two points on the graph of a relation, it is <em>not </em>a function. A relation which is not a function. The x-intercept of a function is calculated by substituting the value of f(x) as zero. Similarly, the y-intercept of a function is calculated by substituting the value of x as zero. The slope of a linear function is calculated by rearranging the equation to its general form, f(x) = mx + c; where m is the slope.

A relation that is not a function

As we can see duplication in X-values with different y-values, then this relation is not a function.

A relation that is a function

As every value of X is different and is associated with only one value of y, this relation is a function.

Step-by-step explanation:

It's up there!

God bless you!

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3 years ago
How do you multiply -6 with 24.50
GrogVix [38]
The answer to the question

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3 years ago
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