Write an equation. To do this, make one integer equal to x, and the other equal to x+1. Set these equal to 149. Your equation should read x+(x+1)=149. Solve. To do this, add the two x's together. Your equation is now 2x+1=149. Get your x's alone. First, subtract 1 from both sides. Now the equation is 148=2x. Divide both sides by 2 to get x alone. You now have x=74. Plug this value back into the original equation to find your value for the other integer, and you have the two integers as 74 and 75. Hope this helps!
Answer:
theres no solution
Step-by-step explanation:
There are no values of x that make the equation true.
No solution
Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .<span>X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 30/5 = 6.Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 30/-3 = -10.Slope is -5/-3 = 1.66666666666667.<span> Equation in slope-intercept form: y=1.66666666666667*x+-10.</span></span>
9514 1404 393
Answer:
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.
