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3 years ago

5

To be safe, you should ____ a. Always reduce your speed at an intersection B. Reduce your speed at an intersection if there is a

flashing yellow light C. Reduce your speed at an intersection if there's a traffic light

1 answer:

uranmaximum [27]3 years ago

8 0

You should always reduce your speed at an intersection, so the answer would be a

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Caveman Clubs Inc. tested a new graphite golf club that they have developed, Model X-5. They did a series of experiments with go

Ostrovityanka [42]

Answer:

The Answer is B. Quantitative data

Explanation:

The testing on the golf club, determined a improvement in the driving distance and this was measured numerically and showed in form of a percentage in comparison with average measurements.

When the information is presented with numerical data support, we can say its a quantitative data, because it tells us "how much?".

When the information is presented just with adjetives, telling us about the performance its a qualitative data, because it tell us "how things happened?"

A control variable is the data that is going to modified in order to see changes is the independent variable. In this case, the control variable could be the weight of the club (assumption), and the independent variable the driving distance data(not percentage).

4 0

3 years ago

What factors are involved when there is an interaction between a person and an experience?

olganol [36]

Answer:

The correct answer is letter "A": sociocultural factors.

Explanation:

Sociocultural factors represent the behavior of societies in different matters and how they can affect individuals. They are mainly driven by the difference among people in the same community and how they interact. Those factors could be <em>religion, ethnicity, </em>and <em>culture</em> to mention a few.

5 0

3 years ago

Sheridan Company issued $6,500,000 of 6%, 10-year bonds for $5,614,000. The straight line method of amortization is to be used.

Mrac [35]

Answer:

The solution of the given query is explained throughout the segment below.

Explanation:

The given values are:

Company issued amount,

= $6,500,000

Rate of interest,

= 6%

Time,

= 10 years

Now,

On bonds payable amortization, the discount will be:

= $\frac{6,500,000 -5,614,000}{10}$

= $\frac{886,000}{10}$

= $88,600$ ($)

Interest expenses will be:

= $(6,500,000\times 6 \ percent) + 88,600$

= $390,000+88,600$

= $478,600$ ($)

5 0

3 years ago

Culver Corporation purchased machinery on January 1, 2022, at a cost of $288,000. The estimated useful life of the machinery is

Digiron [165]

Answer:

Instructions are below.

Explanation:

Giving the following information:

Purchasing price= $288,000

Useful life= 4 years

Salvage value= $33,800

First, we will calculate the depreciation expense using the straight-line method:

Annual depreciation= (original cost - salvage value)/estimated life (years)

Annual depreciation= (288,000 - 33,800)/4

Annual depreciation= $63,550

Now, using the double-declining balance:

Annual depreciation= 2*[(book value)/estimated life (years)]

Year 1= 2*63,550= 127,100

Year 2= [(254,200 - 127,100)/4]*2= $63,550

Year 3= [(127,100 - 63,550)/4]*2= $31,775

Year 4= [(63,550 - 31,775)/]*2= $15,887.5

6 0

3 years ago

You wish to retire in 20 years, at which time you want to have accumulated enough money to receive an annual annuity of $24,000

den301095 [7]

Answer:

$3,286.52

Explanation:

Interest rate per annum = 12.00%

Number of years = 25

Number of compounding per per annum = 1

Interest rate per period (r) = 12.00%

Number of periods (n) = 25

Payment per period (P) = $24,000

PV of $24,000 payments after 20 years = P * [1 - (1/(1+r)^n)]/ r

PV of $24,000 payments after 20 years = 24000*[1-(1/(1+12%)^25]/12%

PV of $24,000 payments after 20 years = $188,235.34

Interest rate per annum = 10.00%

Number of years= 20

Number of payments per per annum = 1

Interest rate per period (r) = 10.00%

Number of periods (n) = 20

Future value of annuity (FVA) = $188,235

Annual contribution (P) = FVA/ ([ (1+r)^n - 1] / r)

Annual contribution (P) = 188235/(((1+10%)^20-1)/10%)

Annual contribution (P) = $3,286.52

5 0

2 years ago