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ryzh [129]
4 years ago
13

A rectangular prymaid is sliced to its base as shown in the figure.

Mathematics
1 answer:
Furkat [3]4 years ago
7 0
The answer is D: rectangle
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the perimeter of an equilateral triangle is 63 inches. if the length of each side is (4x-3), find the value of x
Ber [7]
Use the equation 4x-3=63
4 0
3 years ago
6 labour complete a work in 12 days. How many labours should added to complete the works in 8 days?​
mario62 [17]

Answer:

9 labours

Step-by-step explanation:

In order to solve this, we must know which kind of proportionality is this. There are two types of proportions, direct and indirect/inverse proportions. In direct proportion, if one quantity increases, the other quantity also increases.

In indirect proportion, if one quantity increases, the other decreases and vice versa.

As per this question, we know if the number of labour increases, the number of days to complete a work decreases, thus proving that this is an indirect/inverse proportion.

6 labours => 12 days

x labours =>  8 days

Since its an inverse proprotion, multiply 6 with 12, and x with 8.

8x = 6 × 12

x = \frac{6*12}{8}

∴ x = <u>9 labours</u>

7 0
3 years ago
Can two different integers have the same absolute value?
kotegsom [21]
8 and -8 both of their absolute values are 8
6 0
3 years ago
Read 2 more answers
How to solve for x where (2^x)*x =n?
Molodets [167]
Tough call.  
You may have to use Newton's Method or something like that.
Graph y=2^x and then graph n/x on the same set of axes.  You may have to assign some arbitrary value to n to make this work.  From the graph you can read off the approximate coordinates of the point of intersection.
4 0
3 years ago
K=mv^2/2 solve for v
matrenka [14]

Answer: v=\sqrt[]{\frac{2K}{m} }

Step-by-step explanation:

K=\frac{mv^2}{2}

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

2*K=\frac{mv^2}{2}*2

2K=mv^2

Divide by m to isolate v^2.

\frac{2K}{m}=\frac{mv^2}{m}

\frac{2K}{m} =v^2

To eliminate the square and isolate v, extract the square root.

\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}

\sqrt[]{\frac{2K}{m} }=v

let's rewrite it in a way that v is in the left side.

v=\sqrt[]{\frac{2K}{m} }

4 0
3 years ago
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