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beks73 [17]
3 years ago
9

How many solutions does the following equation have? |4x + 12| = 0 No solution One solution Two solutions Infinitely many soluti

ons

Mathematics
1 answer:
likoan [24]3 years ago
5 0
Hello,
Here is the graph of y=|4x+12| which is null for x=-3.

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F is between E and G. Find FG if EG = 25, EF= 2x – 6 and FG = 4x + 7
KonstantinChe [14]

Answer:

23+ 37 = 42

the EG is congruent to the FA and therefore have to dividee the value to get 302

5 0
3 years ago
Para reunir dinero para su gira de estudios , los alumnos de un curso deciden vender números de una rifa que se encuentran numer
QveST [7]

Respuesta:

0.53

Explicación:

Para calcular la posibilidad del evento A: "ganar la rifa comprando todos los números múltiplos de 3 o 5", debemos usar la siguiente fórmula.

P(A) = casos favorables / casos posibles

Evaluemos primero todos los casos que son múltiplos de 3, entre 1 y 100: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96, 99. En total son 33.

Ahora, evaluemos todos los casos que son múltiplos de 3, entre 1 y 100: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100. En total son 20.

El número total de casos favorables es 33 + 20 = 53.

El número de casos posibles es el total de números de 1 a 100, es decir 100.

Luego P(A) = 53/100 = 0.53.

7 0
2 years ago
It is estimated that 26% of the population of Gingerland have red hair. If 10 residents are chosen at random, what is the probab
sveticcg [70]

Answer:

The answer for me would be a) exactly 4 of them have red hair

Step-by-step explanation:

being that there is 26 percent of people in Gingerland that gave red hair I cam assume that that is a lot of people being that Gingelrand is like a city/town so exactly 4 of them is what I assume is the amswer

6 0
3 years ago
Find a set of four integers such that their order and the order of their absolute values are the same.
Vinvika [58]

If you pick only positive numbers, the absolute value will have no effect, and the original set and the set of the absolute value will be exactly the same:

A = \{1,2,3,4,5\}

is still

A = \{|1|,|2|,|3|,|4|,|5|\} = \{1,2,3,4,5\}

8 0
3 years ago
PHOTO ATTACHED.. please help
Katyanochek1 [597]
The correct answer is 3n-1
8 0
3 years ago
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