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earnstyle [38]
3 years ago
11

Which translation will change figure ABCD to figure A'B'C'D'?

Mathematics
2 answers:
Montano1993 [528]3 years ago
7 0
7 units left, 6 units up
madam [21]3 years ago
4 0
Answer is A. 7 units left and 6 units up
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Answer the following questions step by step with explanations!<br><br>1 × 2 × 3 ÷ 1 × 0 + 6​
pogonyaev

Answer:

6

Step-by-step explanation:

Since there in a time 0 in the equation, anything before that is useless. afte that its a +6 so its 6

hope it helps

3 0
3 years ago
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Deon earns $91 washing 7 dogs. At this rate, how many dogs did Deon wash to earn $117?​
mamaluj [8]
$91/ 7 = $13 per dog
$117/$13 = 9 dogs
He washed 9 dogs
4 0
3 years ago
leontyne sings for $1,000 an hour. Her rate increases by 50 percent after midnight. If she sings one night from 8:30 pm until 1:
iren2701 [21]
From 8.30 pm to 12 : 00

Difference = 12 : 00 - 08:30 = 3 : 30

3 hours 30 minutes = 3.5 hours.

Total for those hours = 3.5 * 1000 = $3500

From 12:00 to 1:00 am  = 1 hour.

50% increase =  50% of 1000 = .50 * 1000 = 500

So it will increase to 1000 + 500 = $1500 per hour.

For the 1 hour extra, 1 * 1500 = $1500

Total = $3500 + $1500 = $5000

She will be paid $5000
4 0
4 years ago
Which pair of angles is a pair of corresponding?
Agata [3.3K]

Answer:

3 and 8 is a pair of corresponding.

8 0
3 years ago
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The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,
tensa zangetsu [6.8K]

We have the following data set:

2,7,15,3,12,9,15,8,3,10

The range is the difference between the highest and lowest values in the set, to find the range, order the data set from least to greatest.

2,3,3,7,8,9,10,12,15,15

Then,

\begin{gathered} \text{Range}=15-2 \\ \text{Range}=13 \end{gathered}

Mean is represented by the following expression:

\text{Mean}=\frac{\text{Sum of all data points}}{Number\text{ of data po}ints}\text{Mean}=\frac{84}{10}=8.4

Population variance formula looks like this:

\begin{gathered} \sigma^2=\frac{\sum^{}_{}(x-\mu)^2}{N} \\ \text{where,} \\ \sigma^2=\text{population variance} \\ \sum ^{}_{}=addition\text{ of} \\ x=\text{each value} \\ \mu=population\text{ mean} \\ N=\text{ number of values in the population} \end{gathered}

Then, substituting:

\begin{gathered} \sigma^2=\frac{(2-14)^2+(3-14)^2+\cdots+(15-14)^2}{10} \\ \sigma^2=20.44 \end{gathered}

For the standard deviation:

\begin{gathered} s=\sqrt[]{\frac{\sum ^{}_{}(x-\mu)^2}{N}} \\ s=4.521 \end{gathered}

5 0
2 years ago
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