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natita [175]
3 years ago
6

Write the factors for each number Then decide whether the number is prime or composite

Mathematics
1 answer:
Lina20 [59]3 years ago
8 0

Answer:

Step-by-step explanation:

If it have more than 2 divider its composite but its divider is only one and its self only its prime.1 isn't neither prime nor composite

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Alex has a truck. 42% of the miles he drove last month were for work. If Alex drove 588 miles for work, how many miles did he dr
Novosadov [1.4K]

Answer:

Step-by-step explanation:

1.588x42=

2. answer - 588=

3 0
3 years ago
How do i graph this NEED ASAP​
mr_godi [17]

this is the step I hope my answer help you .

6 0
3 years ago
If you help me just explain it to me
love history [14]

Answer:

C

Step-by-step explanation:

lets find median 2, 4, 4, 5, 6, 8, 9, 10, 10, 13, 17

now lets find the lower quartile median and upper quartile median

we don't include the median in the count, only use it to divide the data into the two parts,

2, 4, <u>4</u>, 5, 6, 8, 9, 10, 10, 13, 17

so lower quartile median is 4,

2, 4, <u>4</u>, 5, 6, 8, 9, 10, <u>10</u>, 13, 17

while upper quartile median is 10

the box represents the range between the upper quartile median and lower quartile median, thus is should go from 4 to 10 with the middle line, representing the median at 8,

the whiskers represent the whole data range

thus, the answer is C

6 0
3 years ago
4-2 1/4 <br> as a fraction !!!<br> ill mark !!<br> have a good day !!
noname [10]

Answer:

3/4

Step-by-step explanation:

it's for sure 3/4!!!!!

7 0
3 years ago
Question 13 plz show ALL STEPS so I can learn thnx
evablogger [386]

9514 1404 393

Answer:

  a) (x³ -x² +x +2) +2/(x+1)

  b) (x² +2x -5) +6/(x+3)

Step-by-step explanation:

Polynomial long division is virtually identical to numerical long division, except that the quotient term does not require any guessing. It is simply the ratio of the leading terms of the dividend and divisor. As with numerical long division, the product of the quotient term and the divisor is subtracted from the dividend to form the new dividend for the next step.

The process stops when the dividend is of lower degree than the divisor.

In part (a), you need to make sure the dividend expression has all of the powers of x present. This means terms 0x³ and 0x² must be added as placeholders in the given dividend. They will become important as the work progresses.

7 0
3 years ago
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