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zhenek [66]
4 years ago
11

A convex pentagon has the following measurements for its interior angles: (x-8), (3x-11), (x+8), (x), and (2x+7). Which of the f

ollowing could be measurements for interior angles of the pentagon? Select all that apply.
A: 60



B: 68



C: 76



D: 108



E: 193



F: 540
Mathematics
1 answer:
Flura [38]4 years ago
6 0
The correct answer isthe sum of all the internal angles of a convex pentagon is 540. Also, if the pentagon is regular, each of its internal angles measures 108 degrees. Therefore, the correct answers for this case would be:The value of x can be found as the sum: x + (x + 8) + (3x-11) + (x-8) + (2x + 7) = 540 resulting in x = 68.Then, (68 + 8) = 76; (3 * 68-11) = 193; (68-8) = 60; (2 * 68 + 7) = 143 and (x) = 68The correct answers are: B: 68, E: 193, C: 76, A: 60. 
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James is incorrect as Alisha runs further than James each week.

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Please help me with this math :)
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Answer:

The X is equal to 1.75

Step-by-step explanation:

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Complete the two-column proof by providing a reason for each of the five statements. Given: Rectangle R U T S Prove: ∠ U S R = ∠
Fantom [35]

Answer:

The two column proof can be presented as follows;

Statement                 {}                              Reason

1. RUST is a rectangle              {}              Given

2. RU = ST ; UT = RS             {}                  Definition of a rectangle

3. ∠STU and ∠SRU are right angles  {}    Definition of a rectangle

4. ΔURS ≅ ΔSTU                  {}                   By SAS rule of congruency

5. ∠USR = ∠SUT                 {}                     By CPCTC            

Step-by-step explanation:

Given that the side RU, the angle ∠SRU and the side RS of triangle ΔURS are congruent to the side ST the angle ∠STU and the side UT of triangle ΔSTU, then ΔURS is congruent to ΔSTU, by the Side-Angle-Side (SAS) rule of congruency

Therefore, we have that ∠USR ≅ ∠SUT and therefore, it can be shown that ∠USR = ∠SUT using the Congruent Parts of Congruent Triangle are Congruent (CPCTC) postulate.

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3 years ago
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One factor of One factor of f(x)=5x^3+5x^2-170x + 280 is (x +
SpyIntel [72]

Answer:

x = –7, x = 2, or x = 4 are factors of f(x).

Step-by-step explanation:

Given : f(x)  = 5x³ +5x²-170x +280 and x + 7 is one factor .

To find  : What are all the roots of the function.

Solution :  f(x)  = 5x³ +5x²-170x +280 .

We have given that x + 7 is factor that mean x = -7 is factor of f(x )

When we divide f(x) by x +7 we get

5x² -30x +40 =0

Taking common 5 from equation

5( x² -6x +8) =0

On dividing by 5 both sides

x² -6x +8 = 0

On factoring

x² -2x -4x +8 = 0.

Taking common x from first two terms and -4 from last two terms

x ( x -2) -4 (x -2) = 0

On grouping

(x-2) (x-4) = 0

x -2 =0

x =2

x-4 =0

x = 4

Therefore, x = –7, x = 2, or x = 4 are factors of f(x).

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4 years ago
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