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mylen [45]
3 years ago
15

We are drawing a single card from a standard 52- deck. Find the following probability. P(two | no face card)

Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0
If I understood the given, you have to find the probability of drawing a "2".
We have four "2's" in a deck of 52 cards, the P(2) = 4/52 = 1/13 =0.0769 ≈0.077
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2 years ago
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tia_tia [17]

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3 years ago
✨Help me out please ✨
alexira [117]
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3 years ago
What is the sum of a 12-term arithmetic sequence where the last term is 13 and the common difference is -10?
Y_Kistochka [10]
\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=12\\
d=-10\\
a_{12}=13
\end{cases}
\\\\\\
a_{12}=a_1+(12-1)d\implies 13=a_1+(12-1)(-10)
\\\\\\
13=a_1-110\implies \boxed{123=a_1}

\bf \\\\
-------------------------------\\\\
\textit{sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n}{2}(a_1+a_n)\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
a_n=\textit{value of the }n^{th}\ term\\
------------\\
n=12\\
a_1=123\\
a_{12}=13
\end{cases}
\\\\\\
S_{12}=\cfrac{12}{2}(a_1+a_{12})\implies S_{12}=\cfrac{12}{2}(123+13)

and surely you know how much that is.
6 0
3 years ago
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