Question

The sum of two integers is 60 and their difference is 4. Find the integers

Answer 1

Answer:

The integers are 32 and 28 .

Solution:

Let the two integers be x and y.

It is given that sum of two integers is 60. Writing it in equation form we get,

$x + y = 60$ ……………..(Let this be equation 1)

Again it is given that, the difference between the two integers is 4. Writing it in equation form we get,

$x-y=4$………………….(let this be equation 2)

Adding Equation 1 and equation 2 we get,

$x+y+x-y=60+4$

$\Rightarrow 2 x=64$

$\Rightarrow \mathrm{x}=\frac{64}{2}$

$\Rightarrow x=32$

Substituting the value of x = 32 in equation 2 we get

$32-y=4$

$\Rightarrow 32-4=y$

$\Rightarrow 28=\mathrm{y}$

Therefore, the two integers are 32 and 28.  

Answer 2

Answer:

28 and 32

Step-by-step explanation:

28 plus 32 equals 60 and 32 minus 28 equals 4.