Question

Help with this math question please

Answer 1

First you need to calculate the value of x when
${x}^{2} + 4x = 45$
the value of x for that is x=-9 or x=5. then on the number line, you will have three different intervals which are:
$x < - 9$
$- 9 < x < 5$
$x > 5$

then you need to choose one number from each of the three intervals to test if you can get
${x}^{2} + 4 < 45$
if you can, then that interval is one of the answer.
so the final answer for this question is
$- 9 < x < 5$