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lakkis [162]
3 years ago
10

What percent of team B’s mean absolute deviation is the difference in the means?

Mathematics
2 answers:
anastassius [24]3 years ago
7 0

Answer:

9%

Step-by-step explanation:

poizon [28]3 years ago
5 0
<h2>The difference between the mean time is about 16 times the mean absolute deviation of the data sets.</h2>

Step-by-step explanation:

We know the mean and absolute mean deviation of two team in a tables as:

                                             Team A      Team B

             Mean                       127.9s          127.4s

Mean absolute deviation     0.26s           0.23s

The difference of mean between two team A and B = 0.5 s

Also,

The difference of mean absolute deviation = 0.03 s

Now, let the difference of the mean times be equal to n times the difference of the mean absolute deviation of two teams.

0.5 = n x 0.03

n = 16.667 (Approx 16)

Therefore, the difference between the mean time is about the 16 times the absolute deviation of the data sets.

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