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blsea [12.9K]
4 years ago
8

Write each fraction as a decimal. round to the nearest hundredth if necessary.

Mathematics
2 answers:
Alona [7]4 years ago
4 0

Answer:

3/8 = 0.375

7/5 = 1.4

21/7 = 3.0

5/3 = 1.666667

Found using my calculator

SashulF [63]4 years ago
3 0

Answer:

0.375

1.4

3

1.66666666667

Step-by-step explanation:

Divide the numerator (top number) by the denominator (bottom).

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What function equation is represented by the graph?
n200080 [17]

Answer:

f(x) = (2/3)x-2

Step-by-step explanation:

Pick any two points and calculate the slope.  I chose:  (-3,-4) and (3,0).  The Rise/Run, or slope, is (0-(-4))/(3-(-3) or 4/6:  2/3

The y-intercept of the graph is -2 ( the value of y when x=0).

Given y = mx + b

we have

y = (2/3)x - 2

<u>Option 3</u>

<u></u>

5 0
2 years ago
30 + -30= 0
Naily [24]

Answer:

Here are some possibilities:

a.) 9 + -9 = 0

b.) 8 + 2 + -10 = 0

c.) 6 + 4 + -2 + -8 =0

3 0
3 years ago
Read 2 more answers
-11, -7 , -3 what is the next integer in the pattern​
Alenkasestr [34]

Answer: 1

Step-by-step explanation:

-11, -7, -3...

you add 4 each time so the next number would be 1

6 0
2 years ago
Read 2 more answers
One container of Tums® costs 4.00 dollars. Each container has eighty 1.00 g tablets. Assume each Tums® is 40.0 percent CaCO₃ by
Anna007 [38]

Answer:

The total cost is 1.25 dollars.

Step-by-step explanation:      

The reaction between HCl and CaCO₃ is giving by:

2HCl(aq) + CaCO₃(s)   →   CaCl₂(aq) + CO₂(g) + H₂O(l) (1)

0.500L     M: 100.01g/mol        

0.400M

According to equation (1), 2 moles of HCl react with 1 mol of CaCO₃, so to neutralize HCl, we need the next amount of CaCO₃:

m CaCO_{3} = (\frac{1 \cdot mol HCl}{2}) \cdot M_{CaCO_{3}} = (\frac{0.500L \cdot 0.400 \frac {mol}{L}}{2}) \cdot 100.01 \frac{g}{mol} = 10.001 g      

The CaCO₃ mass of each tablet is:

m CaCO_{3} = 1 g_{tablet} \cdot \frac{40g CaCO_{3}}{100g_{tablet}} = 0.4g

Hence, the number of tablets that we need to neutralize the HCl is:

number_{tablets} = ( \frac{1 tablet}{0.4 g CaCO_{3}}) \cdot 10.001g CaCO_{3} = 25  

Finally, if every 80 tablets costs 4.00 dollars, 25 tablets will cost:

cost = (\frac {4 dollars}{80 tablets}) \cdot 25 tablets = 1.25 dollars

<u>So, the total cost to neutralize the HCl is 1.25 dollars.</u>

I hope it helps you!

7 0
3 years ago
What is the answer to <br> 4(3C-2)=12(C+2)
Elis [28]

Step-by-step explanation:

4(3c-2)=12(c+2)

12c-8=12c+24

12c-12c=24+8

0=32

7 0
3 years ago
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