
There are
of each suit in a deck of
cards.
This means the probability of drawing a diamond card is
. You can divide the numerator and denominator each by
to simplify. 
Since there are the same number of clubs as there are diamonds, the probabilities are the same.
<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
7 raised to power of 1 is 7
Answer is 7
Hope this helps
Wouldnt it be the out side numbers ?at both ends?
Doing (7x÷7) I think equals 1