Answer: 
Step-by-step explanation:
All you need do is to rationalize , that is :
X 
= 
= 
That number as a fraction is 19/18
X − 4y = 7
5x + 9y = 6
5x − 20y = 35 //1st * 5
5x + 9y = 6
5x +9y - 5x + 20y = 6 - 35 //2nd - 1st
5x + 9y = 6
29y=-29
5x=6-9y
y=-1 //1st : 29
5x=6-9*(-1)
y=-1
x=15:5 //2nd : 5
y=-1
x=3
check:
for x=3 and y=-1 there is:
x − 4y = 7 is 3 − 4*(-1) = 7 is 7=7 ok
5x + 9y = 6 is 15-9=6 is 6=6 ok
answer: (3;-1) represents the solution.
Answer:
0.8041
Step-by-step explanation:
We know that
μ=72 and σ=5
and P(65<X<78)
We can determine the Z value as (X-μ)/σ
P( 65<X<78 )=P( 65-72< X-μ<78-72)


To fine the Z values:

From the standard normal tables:

to find P ( Z<-1.4)

From the standard normal tables:

Therefore


Answer:

Step-by-step explanation:
Since opposite and adjacent is given, we will use tan as trigonometric ratio.
Hence,
opposite = x , adjacent = 14 and
= 28
So,

tan 28 = x / 14
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>