2 years ago

Square root -9/(3-2i) + (1+5i)

Mathematics

1 answer:

stiv31 [10]2 years ago

5 0

Answer: i 53°17'37

hopefully

Step-by-step explanation:

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Find all the square roots of x2 ≡ 53 (mod 77)

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Answer:

$x=\pm\sqrt{77n+53}$

Step-by-step explanation:

We have been given an equivalence equation $x^2\equiv 53\text{ (mod } 77)$ . We are asked to find all the square root of the given equivalence equation.

Upon converting our given equivalence equation into an equation, we will get:

$x^2-53=77n$

Add 53 on both sides:

$x^2-53+53=77n+53$

$x^2=77n+53$

Take square root of both sides:

$x=\pm\sqrt{77n+53}$

Therefore, the square root for our given equation would be $x=\pm\sqrt{77n+53}$ .

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