A car is worth $300
Step-by-step explanation:
A board game allows players to trade and sell game pieces of equal value
- Player 1 traded three cars plus $100 for a house
- Player 2 sold two houses and a car for $2300
We need to find how much the car is worth
Assume that the car is worth $x and the house is worth $y
∵ Player 1 traded three cars plus $100 for a house
∴ 3 x + 100 = y
- Subtract 100 from both sides
∴ 3 x = y - 100
- Subtract y from both sides
∴ 3 x - y = - 100 ⇒ (1)
∵ Player 2 sold two houses and a car for $2300
∴ x + 2 y = 2300 ⇒ (2)
Now we have system of equation to solve it
Multiply equation (1) by 2 to eliminate y
∵ 6 x - 2 y = - 200 ⇒ (3)
- Add equations (2) and (3)
∴ 7 x = 2100
- Divide both sides by 7
∴ x = 300
A car is worth $300
Learn more:
You can learn more about the system of equations in brainly.com/question/6075514
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<em><u>Complete Question:</u></em>
What is the y intercept of y = -3-7x
<em><u>Answer:</u></em>
<h3>The y intercept is (0, -3)</h3>
<em><u>Solution:</u></em>
<em><u>Given equation is:</u></em>
y = -3 - 7x
The y intercept is the point where the line crosses the y axis
<u>Finding y intercept:
</u>
To determine the y-intercept, we set x equal to zero and solve for y
Substitute x = 0 in given equation
y = -3 - 7(0)
y = -3 - 0
y = -3
Thus the y intercept is (0, -3)
A = <span>π r^2
A =78.54 yards</span>
Answer:
The correct option is D.Any real number value of x satisfies the equation.
Hope it helps.............