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3 years ago

7

About 6% of the population has a particular genetic mutation. 600 people are randomly selected. find the standard deviation for

the number of people with the genetic mutation in such groups of 600.

1 answer:

Rina8888 [55]3 years ago

7 0

Assume a binomial distribution. Then the mean of the distribution is $np$ , where $n$ is the number of people taken in a sample and $p$ is the probability of the mutation occurring in any given person, and the standard deviation is $\sqrt{np(1-p)}$ . Then in this case, the standard deviation is $\sqrt{600(0.06)(0.94)}\approx5.82$ .

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Step-by-step explanation:

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In this problem, we have the following second order polynomial:

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