Well,

We can see that there are 8 10's and 3 1's. So we can write 8 10's followed by 3 1's and join them with addition symbols.

83 = 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 1 + 1 + 1

6 0

4 years ago

Read 2 more answers

Wesley can use the equation y=3x to calculate how far he has walked, where y represents the number of miles walked, and x repres

arlik [135]

16.5/3 = 5.5

Step-by-step explanation:

becuase he needs to walk 16.5 miles. and he can walk 3 miles per x(hour)

you need to devide distance by speed to get time.

5 0

3 years ago

Change these times to 24-hour clock.<br> A- 4:25pm<br> B-3:45 am

ivanzaharov [21]

Are you even in middle school or high school?lol

7 0

3 years ago

Read 2 more answers

A teacher was interested in finding out whether a special study program would increase the scores of students on a national exam

bija089 [108]

Answer:

Check the explanation

Step-by-step explanation:

Going by the first attached image below we reject H_o against H_1 if obs. $T > t_{\alpha /2;n-1}$

here obs.T=1.879

$\therefore obs.T \ngtr 2.447=t_{0.025;6}$

we accept $H_o:\mu _{1}=\mu_{2}$ at 5% level of significance.

i.e there is no sufficient evidence to indicate that the special study program is more effective at 5% level of significance.

this problem is simillar to the previous one except the alternative hypothesis.

Let X_i's denote the bonuses given by female managers and Y_i's denote the bonuses given by male managers.

we assume that $X_i \sim N(\mu _{1},\sigma _{1}^{2}) Y_i \sim N(\mu _{2},\sigma _{2}^{2})$ independently

We want to test $H_0:\mu_{1}=\mu_{2} vs H_1:\mu_{1}\neq \mu_{2}$

define $D_i=X_i-Y_i , i=1(1)8$

now $D_i\sim N(\mu _{1}-\mu _{2}=\mu _{D},\sigma _{1}^{2}+\sigma _{2}^{2}=\sigma _{D}^{2}) , i=1(1)8$

the hypothesis becomes

$H_0:\mu_{D}=0 vs H_1:\mu_{D}\neq 0$

in the third attached image, we use the same test statistic as before

i.e at 5% level of significance there is not enough evidence to indicate a difference in average bonuses .

3 0

3 years ago