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3 years ago

Helppppppppppp please and expalin if you can

Mathematics

1 answer:

Klio2033 [76]3 years ago

8 0

The angle subtended by a diameter is always right. That's Thales' Theorem, one of the first in geometry. We conclude y=90°.

The angle subtended by an arc is half the arc length, so z=50°.

The angles in a triangle add to 180°, so x = 180° - y - z = 40°.

Answer: x=40°, y=90°, z=50°

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How do you find the dimensions of a cylinder (height, radius, diameter and area of the base) when you are given the volume of th

MariettaO [177]

Answer:

Step-by-step explanation:

the formula for a cylinder is πr^2 x H

if it equals 10 to find the others you just need to do algebra

$\pi r^{2} *h = 10$

$h =\frac{10}{\pi r^{2} }$

$r =\sqrt{\frac{\frac{10}{h} }{\pi } }$

to find diameter times it 2

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4 years ago

What is .9 repeating as a fraction

Finger [1]

There is no answer to this because:

Any digit repeating like that would usually be ?/9

Example: 0.1 repeating = 1/9

0.2 repeating = 2/9

0.8 repeating = 8/9

But 0.9 repeating? There should not be a fraction for that.

If you want to round up to 1, you can.

5 0

3 years ago

1) Calculate the quotient 2166 / 38

Tasya [4]

Answer:

Step-by-step explanation:

2166/38=57

4 0

3 years ago

Read 2 more answers

A Prodigiks laptop is sold for $1,189 at a reduction of 18% on its recommended retail price. What was the computer's initial (re

fomenos

Answer:

974.98

Step-by-step explanation:

Is the price of a reduction or sale .

Need 1 more brainliest

greatly appreciated :)

3 0

4 years ago

Can anyone HELP with my HOMEWORK for GRADE‼️

noname [10]

Answer:

The coordinates of point C are (a,0).

Step-by-step explanation:

Given information: ABC is right isosceles triangle.

From the given figure it is noticed that the side BC is hypotenuse of the triangle ABC.

By pythagoras theorem,

$hypotenuse^2=leg^2+leg^2$

$hypotenuse^2=2leg^2$

$hypotenuse=leg\sqrt{2}$

Therefore hypotenuse cannot be equal to leg. So, we can say that in triangle ABC,

$AB=AC$

Length of AB is

$AB=\sqrt{(a-0)^2+(0-0)^2}=a$

From the figure it is noticed that the point C lies on the x-axis, therefore the y-coordinates of C is 0.

Let the coordinates of C be (x,0) and length of AC must be a.

$AC=\sqrt{(x-0)^2+(0-0)^2}$

$a=x$

Therefore coordinates of point C are (a,0).

5 0

4 years ago