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patriot [66]
3 years ago
6

Sam left his school at 3:05. He walked at a speed of 3.2 mph. 15 minutes later, Al started running after him, and he caught up w

ith Sam 10 minutes later. What was Al’s speed?
Mathematics
2 answers:
tatuchka [14]3 years ago
8 0

Answer: 8 miles per hour (mph)

Step by step explanation:  

Given that,

Sam left his school at 3:05

Walked at a speed of 3.2 mph

Al’s speed = ?

AI caught up with Sam 10 minutes later

Speed = distance /time

Sam’s distance  

3.2 x 1/4 = 0.8 miles

At the same time, Al runs for 10 min, which is 1/6 hr.  

Meanwhile in the same 10 minutes, Sam walks 3.2 x 1/6 =0.53 miles.

AI ran the distance of -> 0.8+ 0.53 = 1.3 miles  

According to the above formula  

1/3 divided by 1/6 = 4/3  

4/3 * 6 = 24/3 = 8 mph

 

allochka39001 [22]3 years ago
5 0
At 3:05 sam left for his school at speed of 3.2 miles per hour.
After 15 minutes, thus, around 3:20, Al started running after him.
AL caught up after 10 minutes later.
Als speed
=> 3.2 mph * 60 minutes = 192 miles per minute
=> 192 miles per minute / 15 = 12.8  miles

12.8 miles /10 minutes = 1.28 miles per hour is Als speed.
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Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

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A)H0: μ1 − μ2 = 0

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Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

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<u><em>Difference Scores Calculations</em></u>

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

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Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

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<u><em>Pooled Variance= Sp²</em></u>

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s2x`2 = s2p/n2 = 566.65/20 = 28.33

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