Answer:
1988920000000000
Step-by-step explanation:
1.98892 x 1000000000000000 (15 zeros)
The upper number (in this case 15) indicates the amount of zeros after the 1 (10 is 10^1, 100 is 10^2)
Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t
the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)
A. x=2.5t
y=11(t-4)
when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647
answer is 5.18 hours
A.
x=2.5t
y=11(t-4)
B. 5.18 hours
⓵ To calculate the volume of a right circular cylinder, the formula is π times the radius of the circular base² time the height of the cylinder.
⓶ Now that we know that the equation to calculate the volume of a right circular cylinder is :
V = π x (r²) x h
You need to find the numbers to replace the volume (V) and the height (h) in the formula.
We already know that the volume is 320 square feet and that the height is 20 feet.
So we are left with a formula looking like this :
320 = π x (r²) x 20
⓷ Now we need to find the radius of the circular base! To do so, you need to solve this equation and isolate the “r”. Start by simplifying the right side :
320 = π x (r²) x 20
÷20 ÷20
↓
16 = π x r²
÷π ÷π
↓
5,09 ⋍ r²
√ √
↓
2,26 feet ⋍ r
⓸ Now that we knoe the value of the radius of the circular base, all there’s left to do is multiply this number by two in order to find the diameter of the water tank :
2,26 x 2 = d
↓
4,51 feet ⋍ d
So your final answer is : the diameter of the water tank is about 4,51 feet.
** Since I devided by “π”, all the answers I wrote from that point are rounded to the nearest hundredths just to make things easier to visualize, but I kept all of the decimals when doing the calculations. So it is possible that your answer might differ slightly from mine if you use the rounded numbers to calculate everything. Just keep that in mind!
I hope this helped, if there’s anything just let me know! ☻
There are infinitely many solutions.
Algebraically, we can eliminate 
and try to solve for 
:
Then
which is the equation of an ellipse.
