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disa [49]
3 years ago
8

Solve 8-1divided 2 x6 24 divided by 6

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0
The answer to the question is -44
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DO NOT JUST GIVE ME A NUMBERRRRRR !!!! SHOWWWW STEPSSSS <br><br> 3r-8=-32
Serjik [45]

Answer:

The answer is -8

Step-by-step explanation:

First, add 8 to both sides to separate the 3r from the rest of the terms. Now you have 3r = -24. Divide both sides by 3, and now you have r = -8

4 0
3 years ago
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Abby got an 85% on her test. She got 34 questions right. How many questions were on the test?
elena55 [62]

Answer:

40 questions

Step-by-step explanation:

This is simple

Divide 34 by .85 (Which is 85% in a decimal)

There were 40 questions

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3 years ago
g Suppose I will flip a fair coin until it lands Heads for the first time, and you will receive $2 if the game lasts for 1 round
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Answer:

Step-by-step explanation:

The main idea is that I would like to pay less than what I'm expecting to win, so in that way, I get a profit out of playing this game. Let X be the number of tosses until I get a Heads. By definition, this is a geometric random variable with parameter p = 1/2.

Let Y the amount I received for playing. So, we want to calculate the expected value of Y.

We can calculate it as follows

E[Y] = 2 P(X=1)+ 4 P(X=2)+ 8 P(X =3)  + \dots  = \sum_{n=1}^infty 2^n P(X=n)

Since X is a geometric random variable, we have that P(X=n) = (\frac{1}{2})^{n-1}\frac{1}{2}

Then,

E[Y] = \sum_{n=1}^\infty 2^{n} (\frac{1}{2})^{n-1} \frac{1}{2} = \sum_{n=1}^\infty 2^{n-1} \cdot \frac{1}{2^{n-1}} = \sum_{n=1}^\infty 1 = \infty

So, we expect to have an infinite amount. Given this, we can pay as much as we want to play the game.

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3 years ago
Write as a product. 5a–5a^2–10a^4
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Answer:

-5a(2a^3+a-1)

Step-by-step explanation:

I factored -5a out of 5a -5a^2-10a^4

hope this helped you

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3 years ago
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4 years ago
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