Answer:
22
Step-by-step explanation:
10) S is the midpoint of RT.
Sx= Rx+Tx/2=2
Tx=13
Sy=Ry+Ty/2= -1
Ty= -1
T=(13,-1)
11) Sx=Rx+Tx/2=-4
Rx= -1
Sy=Ry+Ty/2= -6
Ry= -9
R=(-1,-9)
12)B is midpoint of AC.
Bx= Ax+Cx/2=-5
By= Ay+Cx/2= 1
B=(-5,1)
E is midpoint of BD.
Ex= Bx+Dx/2=-4
Dx=-3
Ey=By+Dy/2=-3
Dy=-7
D=(-3,-7)
Answer:
Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.
Step-by-step explanation:
Given:
In Δ PQT
PQ = 30 ft
QT = 28 ft
TP = 20 ft
In Δ QRS
QR = 15 ft
RS = 14 ft
SQ = 10 ft
To Prove:
Δ PQT ~ Δ QRS
Proof:
First we consider the ratio of the sides
..............( 1 )
..............( 2 )
..............( 3 )
So By equation ( 1 ), ( 2 ) and ( 3 ) we get
Now in Δ PQT and Δ QRS we have
Which are corresponding sides of a similar triangle in proportion.
∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved
Answer:
If you draw a right angle and measure it, then it will measure as 90 degrees.
Answer:
On the first equation, which is (c-d)/5 - 2 = 0 Let's start by solving c.
First, you need to add 1/5d to both sides:
1/5 c + -1/5 d - 2 + 1/5 d = 0 + 1/5 d
1/5 c - 2 = 1/5 d
Next, add 2 to both sides:
1/5 c - 2 + 2 = 1/5 d + 2
1/5 c = 1/5 d + 2
Now, divide both sides by 1/5:
1/5 c/ 1/5 = 1/5 d + 2/ 1/5
c = d + 10
so, therefore, your answer is c = d + 10
____________________________________________________________
Now we are going to do the 2nd equation, which is c-6d=0 Lets solve c.
The only thing you need to do is you need to add 6d to both sides:
c − 6d + 6d = 0 + 6d
c = 6d
So, therefore, your answer is c = 6d