In circle X chords AB and CD are congruent and AB is 9 units from X. Find the distance from CD to X. I need help with the steps
I have no idea of how to do it. Please help.
1 answer:
Given: Circle X, Chords AB and CD, AB <span>≅ CD, distance from AB to X is 9.
1. Circle X
1. Given
2. AB and CD are chords of circle X
2. Given
3. </span>AB ≅ CD
<span>3. Given
4. AB is 9 units from X.
4. Given
<em>(You can combine some of these givens into one step if you want)</em>
5. AB and CD are equidistant from X.
5. </span>When ≅ chords are in the same circle, they are equidistant from the center.
6. CD is 9 units from X.
6. Substitution Property <span>■
Refer to the attached image if you need to.</span>
1. Circle X
1. Given
2. AB and CD are chords of circle X
2. Given
3. </span>AB ≅ CD
<span>3. Given
4. AB is 9 units from X.
4. Given
<em>(You can combine some of these givens into one step if you want)</em>
5. AB and CD are equidistant from X.
5. </span>When ≅ chords are in the same circle, they are equidistant from the center.
6. CD is 9 units from X.
6. Substitution Property <span>■
Refer to the attached image if you need to.</span>
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Answer:
a
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - , thus
y = - x + c ← is the partial equation
To find c substitute (- 5, 8) into the partial equation
8 = 1 + c ⇒ c = 8 - 1 = 7
y = - x + 7 ← in slope- intercept form
Multiply through by 5
5y = - x + 35 ( add x to both sides )
x + 5y = 35 ← in standard form → a