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DiKsa [7]
3 years ago
14

Show, using polynomial long division, that: (2x^2+x-14)/(2x-5)

Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0
<u>2x² + x - 14</u> = ¹/₂x r -14
     2x - 5
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Which of the graphs below represents the equation 4x + y = 7?
cupoosta [38]

Answer:

Graph C

Step-by-step explanation:

8 0
3 years ago
Please help ASAP!!!
Ne4ueva [31]

Answer:

Step-by-step explanation:

Find the sum of the squares of the residuals for

y  2x  6

6 0
3 years ago
Three brothers Charlie Robert and Nicholas have 21 video games Charlie has twice as many games as Robert. Robert has 5 fewer gam
AVprozaik [17]

Answer:

The equation would be 4x-15=21.

Step-by-step explanation:

Given;

Total Number of Video games = 21

Let the number of video game Nicholas has be 'x'.

Now Given:

Robert has 5 fewer games than Nicholas.

so we can say that;

number of video game Robert has = x-5

Also Given:

Charlie has twice as many games as Robert.

so we can say that;

number of video game Charlie has = 2(x-5)=2x-10

we need to write the equation.

Solution:

Now we can say that;

Total Number of Video games is equal to sum of number of video game Nicholas has, number of video game Robert has and number of video game Charlie has.

framing the equation we get;

x+x-5+2x-10=21\\\\4x-15=21

Hence The equation would be 4x-15=21.

On Solving we get;

Adding both side by 15 we get;

4x-15+15=21+15\\\\4x=36

Dividing both side by 4 we get;

\frac{3x}{4}=\frac{36}{4}\\\\x=9

Hence Nicholas has = 9 video games

Robert has = x-5= 9-5=4 video games

Charlie has = 2x-10 = 2\times9-10=18-10=8 video games

5 0
3 years ago
Read 2 more answers
By what number should ( -5)(-1) be multiplied so that the product may be equal to (10)(-1)​
Rudik [331]
Answer: -2

(-5)(-1)x=(10)(-1)
5x = -10
x = -2
7 0
3 years ago
Find the coordinates of the three points on the graph of y = (1/2)x² -2x whose x-values are −2, 0, and 4.
MaRussiya [10]

Answer:

y = 6

y = 0

y = 0

Step-by-step explanation:

y=\frac{1}{2}x² -2x

When, x = -2

y=\frac{1}{2}\times (-2)^2-2\times(-2)\\\Rightarrow y=\frac{1}{2}4+4\\\Rightarrow y=2+4\\\Rightarrow y=6

y = 6

When, x = 0

y=\frac{1}{2}\times (0)^2-2\times(0)\\\Rightarrow y=0+0\\\Rightarrow y=0

y = 0

When, x = 4

y=\frac{1}{2}\times (4)^2-2\times(4)\\\Rightarrow y=\frac{1}{2}16-8\\\Rightarrow y=8-8\\\Rightarrow y=0

y = 0

3 0
3 years ago
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