Question

The skip_elements function returns a list containing every other element from an input list, starting with the first element. Complete this function to do that, using the for loop to iterate through the input list.

Answer 1

Answer:

Following are code that we fill in the given in the given question

if i %2==0:# check the condition

new_list.append(elements[i])# append the list  

return new_list # return the new_list

Explanation:

Missing Information :

def skip_elements(elements):# function

new_list=[]# Declared the new list

i=0  #variable declaration

for i in range(len(elements)): #iterating over the loop  

if ---------# filtering out even places elements in the list

--------------# appending the list

return -------- # returning the new_list

print(skip_elements(['a','b','c','d','e','f','g'])) #display

Following are the description of the code:

• In this we declared a function skip_elements .In this function we pass the parameter into them .
• After that we declared the new_list array.
• Declared the variable "i" that are initialized with the 0 value .
• Iterating over the for loop and this loop we check the condition in the if condition.
• The if condition executed when the index is even .The statement inside the if condition we will appending the list and returning the list item .
• Finally we print the even number of index list .