$3 for 6 bagels; $9 for 24 bagels

Joel built a model town. He constructed three buildings that each had a volume of 18 cm cubed. Each building looked different. W

morpeh [17]

Answer:

The three buildings can look like following:

1. The building can look like a cube, with each side and height equal to 2.62 cm.

2. The building can look like a cuboid, with 3 cm length, 1 cm breadth and 6 cm height.

3. The building can look like a pyramid, with 3 cm length, 3 cm breadth and 6 cm height.

Step-by-step explanation:

The three possibilities of the appearance or shape of the building, with the volume equal to 18 cm³ are as follows:

1. CUBIC SHAPE:

The building can look like a cube with the length of each side and height given as:

Volume of Cube = 18 cm³ = L³

L = ∛18 cm³ = 2.62 cm

Thus, the building can look like a cube, with each side and height equal to 2.62 cm.

2. CUBOID SHAPE:

The building can also look like cuboid with the following dimensions.

Length = 3 cm

Breadth = 1 cm

Height = 6 cm

Thus, the volume becomes:

Volume of Cuboid = Length * Breadth * Height

Volume of Cuboid = 3 cm * 1 cm * 6 cm = 18 cm³

Thus, the building can look like a cuboid, with 3 cm length, 1 cm breadth and 6 cm height.

3. PYRAMID SHAPE:

The building can also look like pyramid with the following dimensions.

Length = 3 cm

Breadth = 3 cm

Height = 6 cm

Thus, the volume becomes:

Volume of Pyramid = (Length * Breadth * Height)/3

Volume of Cuboid = (3 cm * 3 cm * 6 cm)/3 = 18 cm³

Thus, the building can look like a pyramid, with 3 cm length, 3 cm breadth and 6 cm height.

5 0

3 years ago

The average heights of x number of girls and 15 boys is 123. if the average heights of boys is 125 and that of girls is 120.find

mamaluj [8]

Answer:

$x = 10$ . In other words, there number of girls is $10$ .

Step-by-step explanation:

The average of a number of measurements is equal to the sum of these measurements over the number of measurements.

$\displaystyle \text{Average} = \frac{\text{Sum of measurements}}{\text{Number of measurements}}$ .

Rewrite to obtain:

$\begin{aligned}& \text{Sum of measurements}= (\text{Number of measurements}) \times (\text{Average}) \end{aligned}$ .

For this question:

$\begin{aligned}& \text{Sum of heights of boys} \\ &= (\text{Number of boys}) \times (\text{Average height of boys}) \\ &= 15 \times 125 = 1875\end{aligned}$ .

$\begin{aligned}& \text{Sum of heights of girls} \\ &= (\text{Number of girls}) \times (\text{Average height of girls}) \\ &= x \times 120 = 120\, x\end{aligned}$ .

Therefore:

$\begin{aligned}& \text{Sum of boys and girls} \\ &= \text{Sum of heights of boys} + \text{Sum of heights of girls}\\ &= 1875 + 120\, x\end{aligned}$ .

On the other hand, there are $(15 + x)$ boys and girls in total. Using the formula for average:

$\begin{aligned}& \text{Average height of boys and girls} \\ &= \frac{\text{Sum of heights of boys and girls}}{\text{Number of boys and girls}} \\ &= \frac{1875 + 120\, x}{15 + x}\end{aligned}$ .