Eight hundred sixty-three and one hundred forty-one thousandths
Since it's a sample size, we use x, as the mean and s= standard deviation
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Given: x =27, s = 2 and total sample = 32.
Probability that a recruit is at least 31 years old?
Let's calculate the Z score :
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X - x 31 - 27
Z = ----------- → Z = -------- → Z = 2 (now look up in the Z score table,
s 2
Area (Z=2) =0.9772 , but Z ≥ 2 (at least) , then :
Area (Z≥2) = Area (Z≤ - 2) = 0.0228
P(≥31)= 0.0228
Part A:
(3x+5)+(3x+5)+(4x-3)+(4x-3)=p
3x+3x+4x+4x=14x
5+5+-3+-3=4
14x+4=p
-4 -4
14x=p-4
---- -----
14 14
x=1/4 p + -2/7
14(1/4 p +-2/7) +4=p
14(0.25p + 0.28571428571)+4=p
3.5 + 3.99999999994 + 4=p
11.4999999999=p
This may not help by no harm in trying.
This question we do not have to over think. We can already answer this with out the help of the diagram. The diagram helps us see that this problem involves the number line. Positive and negative numbers are involved in the number line.
Here how we can think about it: From the middle to the left the length is 39 and to the right it is 19. The length is then 58.
