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Ksivusya [100]
3 years ago
10

Use four unit multipliers to convert 630 square yards into square inches

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
7 0
We are asked to determine the unit multipliers in order for us to convert 630 square yards to into square inches. Well, first we need to convert square yards to square feet and secondly, we convert square feet to square inches.
square yards -> square feet -> square inches
We also take note the following:
1 yard = 3 feet
1 foot = 12 inches
The solution in converting the unit is shown below:
630 yards² * (3 feet / 1 yard)² = 5670 feet²
5670 feet² * (12 inches / 1 foot)² = 816,480 inches²

The answer is 816,480 inches².
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If you deposit $25,000 now at 6.5% compounded quarterly, how much will you have in 30 years?
Mice21 [21]

Answer:

$172,984.44

Step-by-step explanation:

We can use the formula

A = P(1 + \frac{r}{n})^{nt} to compute the final amount

Here P is the principal amount, the original deposit = $25,000

r is the annual interest rate = 6.5% = 0.065 in decimal

n is the number of times the compounding takes place. Here it is quarterly so it is 4 times a year

t is the number of time periods ie 30 years

A is the accrued amount ie principal + interest

Computing different components,

nt = 4 \times 30 = 120

r/n =  0.065/4 = .01625

1 + r/n = 1.01625

(1 + r/n)^{nt} = 1.01625^{120}

Therefore

A = 25000 \times 1.0625^{120} = 172,984.44


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2 years ago
Which triangle is a right triangle?
iren [92.7K]

Answer:

A right triangle is always 90 degrees.

Step-by-step explanation:

4 0
3 years ago
5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

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3 years ago
BESTIES HELP PLEASE!!?!?!?!?&amp;$
8090 [49]

Answer:

Yes no yes yes

Step-by-step explanation:

3 0
3 years ago
write an equation of the line that's passes through the point (1,6) and is parallel to the line whose equation is y= 3x - 5
Alex Ar [27]
Parallel lines have the same slope.
so to find any line, you need a set of points, and a slope.
we already have the slope, being 3.
so, use the equation
y- (y-point)/ x-(x-point)=slope.
y-6. 3
---- = ---- (make it a fraction by puttingitover 1)
x-1. 1
cross multiply.
1(y-6)=3 (x-1)
y-6=3x-3
add 6 to both sides
Final answer: Y=3x+3
7 0
3 years ago
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