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son4ous [18]
3 years ago
9

Gabriel makes a model of a pyramid with the dimensions shown. A square pyramid. The square base has side lengths of 12 inches. T

he triangular sides have a height of 11 inches. Gabriel wants to paint the model. How much paint will he need? The area of the square base is in.2. The area of each triangular face is in.2. Gabriel will need in.2 of paint.

Mathematics
2 answers:
Blizzard [7]3 years ago
8 0

Answer:

The area of the square base is 114 in. 2

The area of each triangular face is 66 in. 2

Gabriel will need 408 in. 2  of paint

murzikaleks [220]3 years ago
8 0
<h2><u><em>Answer</em></u></h2><h2><u><em /></u>144in^{2}<u><em /></u></h2><h2><u><em /></u>66in^{2}<u><em /></u></h2><h2><u><em /></u>408in^{2}<u><em /></u></h2><h2></h2>

<u><em /></u>

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Plz help, I'm taking an Advanced class (Algebra) Will give brainliest ✔✔✔✔✔✔✔✔✔
bija089 [108]

Part A:

The average rate of change refers to a function's slope. Thus, we are going to need to use the slope formula, which is:

m = \dfrac{y_2 - y_1}{x_2 - x_1}

  • (x_1, y_1) and (x_2, y_2) are points on the function

You can see that we are given the x-values for our interval, but we are not given the y-values, which means that we will need to find them ourselves. Remember that the y-values of functions refers to the outputs of the function, so to find the y-values simply use your given x-value in the function and observe the result:

h(0) = 3(5)^0 = 3 \cdot 1 = 3

h(1) = 3(5)^1 = 3 \cdot 5 = 15

h(2) = 3(5)^2 = 3 \cdot 25 = 75

h(3) = 3(5)^3 = 3 \cdot 125 = 375


Now, let's find the slopes for each of the sections of the function:

<u>Section A</u>

m = \dfrac{15 - 3}{1 - 0} = \boxed{12}

<u>Section B</u>

m = \dfrac{375 - 75}{3 - 2} = \boxed{300}


Part B:

In this case, we can find how many times greater the rate of change in Section B is by dividing the slopes together.

\dfrac{m_B}{m_A} = \dfrac{300}{12} = 25


It is 25 times greater. This is because 3(5)^x is an exponential growth function, which grows faster and faster as the x-values get higher and higher. This is unlike a linear function which grows or declines at a constant rate.

7 0
4 years ago
Find the value of x and the value of y for which (x,23) and (18,y) ate the points on the graph y=0.5x+15
shutvik [7]

Answer:

x=16; y=24

Step-by-step explanation:

for (x,23), 23=0.5x+15

x=16

for (18xy), y=0.5*18+15=24

8 0
4 years ago
R=x^2/y <br> x=3.8 times 10^5 <br> y=5.9 times 10^4 <br> work out the value of r
Zinaida [17]

Answer:

  2.4×10^6

Step-by-step explanation:

Put the numbers where the variables are and do the arithmetic. You can enter the numbers in scientific notation into your (scientific) calculator and have it show you the result in the same format.

  r = (3.8×10^5)^2/(5.9×10^4) . . . . . denominator parentheses are required

Please note that in the above expression, parentheses are required around the denominator number. This is because it is a product of two numbers. In your pocket calculator or spreadsheet, you can enter that value as a single number (not a product). Parentheses are not required when you can do that.

  r = (3.8²/5.9)×10^(5·2-4) ≈ 2.4×10^6

___

The "exact" value is a repeating decimal with a long repeat. We have rounded to 2 significant digits here because the input numbers have that number of significant digits.

7 0
3 years ago
Evaluate the limit. lim x-&gt; infinity n/3^x
Sav [38]

Answer:

0

Step-by-step explanation:

Find the following limit:

lim_(x->∞) 3^(-x) n

Applying the quotient rule, write lim_(x->∞) n 3^(-x) as (lim_(x->∞) n)/(lim_(x->∞) 3^x):

n/(lim_(x->∞) 3^x)

Using the fact that 3^x is a continuous function of x, write lim_(x->∞) 3^x as 3^(lim_(x->∞) x):

n/3^(lim_(x->∞) x)

lim_(x->∞) x = ∞:

n/3^∞

n/3^∞ = 0:

Answer:  0

7 0
3 years ago
Needdd hellpppppssssssss
Ratling [72]

Answer:

Choice number one:

\displaystyle \frac{5}{10}\cdot \frac{4}{9}.

Step-by-step explanation:

  • Let A be the event that the number on the first card is even.
  • Let B be the event that the number on the second card is even.

The question is asking for the possibility that event A and B happen at the same time. However, whether A occurs or not will influence the probability of B. In other words, A and B are not independent. The probability that both A and B occur needs to be found as the product of

  • the probability that event A occurs, and
  • the probability that event B occurs given that event A occurs.

5 out of the ten numbers are even. The probability that event A occurs is:

\displaystyle P(A) = \frac{5}{10}.

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

\displaystyle P(B|A) = \frac{4}{9}.

The probability that both A and B occurs will be:

\displaystyle P(A \cap B) = P(B\cap A) =  P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}.

6 0
3 years ago
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