What is the 41st term of the sequence 8,10,12,14....
2 answers:
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Answer:
≈ 12.6
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let x be the third side, then
x² + 6² = 14²
x² + 36 = 196 ( subtract 36 from both sides )
x² = 160 ( take the square root of both sides )
x = ≈ 12.6 ( to the nearest tenth )