A tilted or slanted cylinder has the same volume as its equivalent right cylinder, provided that
(a) the two bases of the tilted cylinder are parallel,
(b) the base areas of the tilted and right cylinders are equal,
(c) the vertical height of the right and tilted cylinders are equal.
This fact can be verified by slicing the tilted cylinder into thin, flat washers, as in integral calculus.
Because all 3 conditions are satisfied, the volume of the tilted cylinder is 450 cm³.
Answer: 430 cm³
First, you need to find the derivative of this function. This is done by multiplying the exponent of the variable by the coefficient, and then reducing the exponent by 1.
f'(x)=3x^2-3
Now, set this function equal to 0 to find x-values of the relative max and min.
0=3x^2-3
0=3(x^2-1)
0=3(x+1)(x-1)
x=-1, 1
To determine which is the max and which is the min, plug in values to f'(x) that are greater than and less than each. We will use -2, 0, 2.
f'(-2)=3(-2)^2-3=3(4)-3=12-3=9
f'(0)=3(0)^2-3=3(0)-3=0-3=-3
f'(2)=3(2)^2=3(4)-3=12-3=9
We examine the sign changes to determine whether it is a max or a min. If the sign goes from + to -, then it is a maximum. If it goes from - to +, it is a minimum. Therefore, x=-1 is a relative maximum and x=1 is a relative miminum.
To determine the values of the relative max and min, plug in the x-values to f(x).
f(-1)=(-1)^3-3(-1)+1=-1+3+1=3
f(1)=(1)^3-3(1)+1=1-3+1=-1
Hope this helps!!
Answer: 28.6 miles
Step-by-step explanation:
A = pi r^2
A = 3.14 (3)^2
Now multiply 3.14(3)^3
Your answer is 28.26
* Radius is 1/2 of the diameter.
I believe this is right, but im not sure.
Hope it helps :)
