Given a Venn diagram showing the number of students that like blue uniform only as 32, the number of students that like gold uniform only as 25, the number of students that like blue and gold uniforms as 12 and the number of students that like neither blue nor gold uniform as 6.
Thus, the total number of students interviewed is 75.
Recall that relative frequency of an event is the outcome of the event divided by the total possible outcome of the experiment.
From the relative frequency table, a represent the relative frequency of the students that like gold but not blue.
From the Venn, diagram, the number of students that like gold uniform only as 25, thus the relative frequency of the students that like gold but not blue is given by

Therefore,
a = 33% to the nearest percent.
Similarly, from the relative frequency table, b represent the relative frequency of the students that like blue but not gold.
From
the Venn, diagram, the number of students that like blue uniform only
as 32, thus the relative frequency of the students that like gold but
not blue is given by

Therefore,
b = 43% to the nearest percent.
For example:
L plus W
3 plus 6= 9
I plus W
4 plus 6= 10
total: 9+10= 19
(this is just an example)
Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

The margin of error is:

In which:
is the sample mean.
is the standard deviation for the population.
Assuming an uniform distribution, the standard deviation is given by:

In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size is found solving for n when the margin of error is of M = 0.006, hence:





n = 142,282.
A sample of 142,282 should be taken, which is not practical as it is too large of a sample.
More can be learned about the z-distribution at brainly.com/question/25890103
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First one simplifies to 2x + 6 = 2x + 7 which can't be true so this one has No Solution.
Same applies to the second equation ( 5x + 15 = 5x - 15) No solution
also the last one has no solution because it simplifies to 4x + 20 = 4x + 19
Answer: your answer is 32/51
Step-by-step explanation: