Hey there! I'm happy to help!
Let's say that we don't have jokers. In that case, there are 52 cards, and half of them are red (so 26 are red). The probability of pulling a red card once is 1/2 since half the cards are red.
If we pick one out, there are only 51 total cards left and 25 red cards. So, the probability of picking one again would be 25/51.
We multiply the probabilities of these two events to find the probability of them both happening.
1/2×25/51=25/102
The probability of picking two red cards in a row is 25/102 or around 24.5%.
Have a wonderful day! :D
Answer:
5 5/6
Step-by-step explanation:
Change them into improper fractions. Multiply the denominator by the whole number and then add the numerator. Put that number over the denominator.
2 X 3 = 6 3 X 2 = 6
6 + 1 = 7 6 + 1 = 7
7/3 7/2
New expression: 7/3 + 7/2
Find a common denominator. Both denominators can go into 6.
14/6 + 21/6 = 35/6
Change this back into a mixed number by dividing.
Answer: 5 5/6
When calculating consecutive integers, the smaller number is x and the larger number is (x + 1).
So the equation you can use is x + (x + 1) = 5 + 3(x + 1)
This is because the sum of the consecutive integers are equal to 5 more than 3 times the larger integer.
Now simplify:
x + (x + 1) = 5 + 3(x + 1)
2x + 1 = 5 + 3(x + 1)
2x + 1 = 5 + 3x + 3
2x + 1 = 3x + 8
Now isolate the variable:
2x + 1 = 3x + 8
Subtract 2x from both sides:
1 = x + 8
Subtract 8 from both side:
-7 = x
x = -7
So the smaller number is -7 and the larger number is -6.
Now check your answer:
-7 + (-7 + 1) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 - 6 = 5 + 3(-7 + 1)
-13 = 5 + 3(-7 + 1)
-13 = 5 + 3(-6)
-13 = 5 + (-18)
-13 = 5 - 18
-13 = -13
This works!
So the integers are -7 and -6.
Same . It’s not giving me a lot of information!!
Brainly is erroneously preventing my response from being posted due to nonexistent profanity or links. So, I have converted my answer into an image file, which I have attached. I also attached an annotated diagram of the figure in the image you posted. Please let me know if you have trouble accessing either. Hope this helps.
