All categories

3 years ago

I would like multiple people to comment w/ their opinion

Mathematics

2 answers:

Leni [432]3 years ago

7 0

The math for this is actually quite simple. Since he can only get as many comics as he can fit into the amount of money he has, you divide the amount he has into the price per comic book. This tells you how many 2.70 there are in 32.40.

32.40/2.70=12

He can buy exactly 12 comic books

abruzzese [7]3 years ago

3 0

He can buy up to 12 comic books

You might be interested in

Which statement correctly describes the expression 6(-16)

dsp73

Answer:

are their answer choices or no ???

8 0

3 years ago

Read 2 more answers

Are the two expressions equivalent when x = 20? 8(12x + 4) 96x + 32

Iteru [2.4K]

Yes
8(12x + 4) = 8[12(20) + 4 ] = 1952

96x + 32 = 96 (20) + 32 = 1952

7 0

3 years ago

The population of rabbits on an island is growing exponentially. In the year 1991, the population of rabbits was 9100, and by 19

lisabon 2012 [21]

Answer:

$39,223\ rabbits$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$y=a(1+r)^x$

where

y is the population of rabbits

x is the number of years since 1991

a is the initial value

r is the rate of change

we have

$a=9,100$

substitute

$y=9,100(1+r)^x$

For the year 1998

the number of years is equal to

x=1998-1991=7 years

we have the ordered pair (7,18,000)

substitute in the exponential equation and solve for r

$18,000=9,100(1+r)^7$

$(18,000/9,100)=(1+r)^7$

elevated both sides to 1/7

$(1+r)=1.1023$

$r=0.1023$

therefore

$y=9,100(1+0.1023)^x$

$y=9,100(1.1023)^x$

Predict the population of rabbits in the year 2006

Find the value of x

x=2006-1991=15 years

substitute the value of x in the equation

$y=9,100(1.1023)^{15}$

$y=39,223\ rabbits$

6 0

3 years ago

The sum of two numbers is 70 and their difference is 30. Find the two numbers

ikadub [295]

Answer:

Our two numbers are 50 and 20

Step-by-step explanation:

Sum means add together

Difference means subtract each other

x + y = 70

x - y = 30

subtract from each other

2x = 100

divide both sides by 2

x = 50

our first number is 50

50 + y = 70

subtract both sides by 50

y = 20

Our two numbers are 50 and 20

8 0

3 years ago

En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,

Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0

3 years ago