Answer:
import java.util.Scanner;
public class Solution {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
int userNum = scan.nextInt();
if (userNum > 0) {
System.out.println("Positive.");
} else {
System.out.println("Non-positive, converting to 1.");
userNum = 1;
System.out.println("Final: " + userNum);
}
}
}
Explanation:
There was no error found when the code was run. The code segment was just added to a main method and it runs successfully.
Based on the full code above;
The first line import the Scanner class which allow the program to receive user input. Then the class was defined as Solution. Then the main method was defined. Inside the main method, we created a scanner object scan which receive the input via keyboard. The user input is assigned to the variable userNum. Then the if-conditional statement is executed; if userNum is greater than 0, "Positive" is output. Else userNum is converted to 1 and outputted to the screen.
Answer:
Following are the analogies to this question:
Explanation:
In each match, the group is a comparison because there may be a tie situation, which already implies, that its triage was unabated, 1 means the best team, and n means the worst team.
It makes it much easier to address whether another 'Quick Sort' or even the 'Merge Sort' issue by converting the very same problem throughout the number problem.
All the cases use for the Merge Sort, in which it utilizes its evenly divide or overcome strategy where the category is reciprocally divided into two parts where the number becomes measured at n==2, and the outcome extends.
Assume we get 7 squads:
2 4 5 4 3 1 6
Recursively split the above teams:
2 4 5 4 3 1 6
2 4 5 4 3 1 6
We'll equate such figures with base-case (n==2) (have a match against each other)
2 4 4 5 1 3 6 (number of matches 1(2,4) + 1(5,4) + 1(3,1) = 3)
Now the division is combined.
1, 2 ,3, 4, 4, 5
NLogN was its best time complexity of an algorithm but N is the lot of clubs.
<span>Here is matlab that should work
% cos(x) = 1 - (x^2)/2! + (x^4)/4! -(x^6)/6!+(x^8)/8!...
% let y= x*x
% cos(x) = sum( (-y)^n/(2n)! )
format short
x= 0.3*pi;
y= x*x;
for N= 1:6
n= 0:N;
s1= [(-y).^n./factorial(2*n) ]
mac= sum(s1);
cx= cos(x);
str= sprintf('%d terms. series: %12.10f cos(x): %12.10f\n %12.10f',...
N, mac,cx, (cx-mac));
disp(str);
end;</span>
The characters in the selected cell.
Answer:
Please check the explanation.
Explanation:
Let x=dependents * ((yearsOnJob - 1) * 4) - 6
where dependents=3
Lets supppose year on job 3
then
x=( 3*((3-1)*4)-6
x= 3*8 -6
= 24-6
=18
And similarly, we can calculate the value of arithmetic expression all the time.
