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sasho [114]
3 years ago
11

Given the following two pair for values x1 = 5, y1 = 4 and x 2 = 1, y2 = .

Mathematics
1 answer:
LiRa [457]3 years ago
6 0

Answer:

Given the following two pair for values x 1 = 5, y 1 = 4 and x 2 = 1, y 2 = .

Calculate the Pythagorean triples associated with each pair

----------------------

x 1 = 5, y 1 = 4

Ans:: sqrt[5^2+4^2] = sqrt[41

 

-----------------------------

and x 2 = 1, y 2 = ?

Ans: r = sqrt[1^2 + ?^2]

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Answer:

4\sqrt{2}.\sqrt{2} = 8\\3\sqrt{7}-2\sqrt{7} =\sqrt{7}\\\frac{\sqrt{7}}{2\sqrt{7}} = \frac{1}{2}\\2\sqrt{5}.2\sqrt{5} = 20

Step-by-step explanation:

4\sqrt{2}.\sqrt{2}\\=4 . (\sqrt{2})^2\\=4*2\\=8\\\\3\sqrt{7}-2\sqrt{7}\\As\ the\ square\ root\ is\ same\ in\ both\ terms\\= (3-2)\sqrt{7}\\=\sqrt{7}\\\\\frac{\sqrt{7}}{2\sqrt{7}} \\The\ square\ roots\ will\ be\ cancelled\\= \frac{1}{2}\\ \\2\sqrt{5}.2\sqrt{5}\\=(2*2)(\sqrt{5})^2\\=4*5\\=20

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Answer:

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And replacing we got:

df= 20+20 -2= 38

And the best answer would be:

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Step-by-step explanation:

For this problem we want to test the following:

Null hypothesis: \mu_1= \mu_2

Alternative hypothesis:\mu_1 =\neq \mu_2

And for this case we assume that we have equal variances so that means:

\sigma =\sigma_1 =\sigma_2

For this case the degrees of freedom are given by:

df= n_1 +n_2 -2

And replacing we got:

df= 20+20 -2= 38

And the best answer would be:

a. 38

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