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sasho [114]
3 years ago
11

Given the following two pair for values x1 = 5, y1 = 4 and x 2 = 1, y2 = .

Mathematics
1 answer:
LiRa [457]3 years ago
6 0

Answer:

Given the following two pair for values x 1 = 5, y 1 = 4 and x 2 = 1, y 2 = .

Calculate the Pythagorean triples associated with each pair

----------------------

x 1 = 5, y 1 = 4

Ans:: sqrt[5^2+4^2] = sqrt[41

 

-----------------------------

and x 2 = 1, y 2 = ?

Ans: r = sqrt[1^2 + ?^2]

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GaryK [48]

Given:

The two points on the graph.

To find:

The distance between the two points in simplest radical form.

Solution:

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Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, the distance between two points (-9,3) and (-3,-2) is:

d=\sqrt{(-3-(-9))^2+(-2-3)^2}

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3 years ago
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How do I solve for x? (the picture has the problem)
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Answer:

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5 0
2 years ago
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11. Keng creates a painting on a rectangular canvas with a width that is four inches longer
GrogVix [38]

Part A

<h3>Answer:  h^2 + 4h</h3>

-------------------

Explanation:

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area = (length)*(height)

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area = h(h+4)

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The units for the area are in square inches.

===========================================================

Part B

<h3>Answer:  h^2 + 16h + 60</h3>

-------------------

Explanation:

If we add a 3 inch frame along the border, then we're adding two copies of 3 inches along the bottom side. The h+4 along the bottom updates to h+4+3+3 = h+10 along the bottom.

Similarly, along the vertical side we'd have the h go to h+3+3 = h+6

The old rectangle that was h by h+4 is now h+6 by h+10

Multiply these expressions to find the area

area = length*width

area = (h+6)(h+10)

area = x(h+10) ..... replace h+6 with x

area = xh + 10x .... distribute

area = h( x ) + 10( x )

area = h( h+6 ) + 10( h+6 ) .... plug in x = h+6

area = h^2+6h + 10h+60 .... distribute again twice more

area = h^2 + 16h + 60

You can also use the box method or the FOIL rule as alternative routes to find the area.

The units for the area are in square inches.

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Answer:

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