Use your calculator to find the smallest solution to
7B2%7Dlog%5Cleft%28x%5E2%2B1%5Cright%29" id="TexFormula1" title="-5e^{-4x+2}+3=\frac{1}{2}log\left(x^2+1\right)" alt="-5e^{-4x+2}+3=\frac{1}{2}log\left(x^2+1\right)" align="absmiddle" class="latex-formula"> and describe the steps you used. Round your answer to three decimals.
I read this as -5e⁻⁴ˣ⁺²+3=½log₁₀(x²+1). If this is not right the steps below can guide you to a possible solution when the correct formula is used. My calculator is a Casio fx-85GT PLUS which has a function facility (MODE 3: TABLE). I input the function: -5e⁻⁴ˣ⁺²+3-½log₁₀(x²+1). I assumed that log was log to base 10 rather than natural log ln. The facility asks me to input a start value, end value and step value. I chose -10, 10 and 1 initially. After a few seconds of evaluating a table of results the calculator showed me the results of plugging in x=-10 up to 10 in steps of 1. The results showed the evaluation for each of the 21 values and I looked for the sign of the result to change. For x=0 the result was -33.95 approx and for x=1 it was 2.1728 approx. So between 0 and 1 there is a zero, a solution for x. I returned to the function and changed the parameters to start=0, end=1, step=0.1 to begin the next evaluation. This time the sign change occurred between x=0.6 and 0.7. I returned to the function with parameters: start=0.6, end=0.7, step=0.01. The sign change occurred between 0.63 and 0.64, the start and end parameters with step=0.001 for the next iteration. The solution is between 0.633 and 0.634. Repeat the process one more time with step=0.0001. The sign change was between 0.6338 and 0.6339 so the solution to three dec places is 0.634.
