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levacccp [35]
3 years ago
11

4. Can the following list represent a complete probability model?

Mathematics
1 answer:
Julli [10]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

probability model must be equal to 1

so summing up the above

P(2)+P(3)+P(4)=1/12+2/3+1/4

=1

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Sarah began the week with $2.60 in her lunch account. She deposited $20 on Monday, and then spent $4.75 each day that week for l
GuDViN [60]

Answer:

The balance in her lunch account at the end of the day on Friday is -$1.15.

Step-by-step explanation:

The balance at the end of the week will be the result of adding up the initial balance with the amount deposited on Monday minus the total amount spent that week.

Initial balance=$2.60

Amount deposited on Monday=$20

Total amount spent that week=$4.75*5=$23.75

Balance=$2.60+$20-$23.75

Balance=$22.60-$23.75

Balance=-$1.15

According to this, the answer is that the balance in her lunch account at the end of the day on Friday is -$1.15.

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Step-by-step explanation:

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Sphinxa [80]

Answer:

n * 7

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7 0
3 years ago
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How long will it take a vehicle to travel 480km at a speed of 75km/h?
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V = d/t
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8 0
3 years ago
For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =
enyata [817]
Given that <span>For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d=v+\frac{v^2}{20}, where [tex]d is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

v+ \frac{v^2}{20} \leq75 \\  \\ 20v+v^2\leq1,500 \\  \\ v^2+20v+100\leq1,500+100 \\  \\ (v+10)^2\leq1,600 \\  \\ |v+10|\leq\sqrt{1,600} \\  \\ -40\leq v+10\leq40 \\  \\ -40-10\leqv\leq v\leq40-10 \\  \\ -50\leq v\leq30

Therefore, the range of speed she can travel is v\leq30\ mi/hr
</span>
8 0
3 years ago
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