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Harrizon [31]
3 years ago
6

Can someone help me

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0
Number one is really easy just set it up in proportions. 420 over x and 7 hours over 24 cause you know there 24 hours in a day and then cross division and simplify. I think.
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Four cakes require 3 1/3 cups of sugar.how much sugar is needed for 5 cakes?
enyata [817]

Answer:

16.6666666

pls crown

3 1/3 *5= 16.6666666

6 0
4 years ago
What substation should be used to rewrite 4x^4-21z^2+20=0
elena-s [515]
\left[x _{4}\right] = \left[ \frac{ - \left( -1\right) ^{\frac{3}{4}}\,\sqrt[4]{\left( 20 - 21\,z^{2}\right) }}{\sqrt[4]{4}}\right][x​4​​]=[​​4​​√​4​​​​​−(−1)​​4​​3​​​​​4​​√​(20−21z​2​​)​​​​​]
I hope helping with u
6 0
4 years ago
Joesphine scored 95, 84, and 87 on three math tests. She wants her average score for 5 tests to be at least 90.
attashe74 [19]

Answer:

The answer for part B is I think 92 and 92. And for part A she could get 97 and 97 as the test average would be 92.

Step-by-step explanation:

I kinda explained it in the answer yeah but I hope that helps.

7 0
3 years ago
Solve X showing every step​
LenKa [72]

Answer:

no solution

Step-by-step explanation:

2x-5=8x+7-6x

2x-5=2x+7

-5=7

Not true so no solution

3 0
3 years ago
The proportion of students at a college who have GPA higher than 3.5 is 19%. a. You take repeated random samples of size 25 from
melomori [17]

Answer:

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=0.0785

Step-by-step explanation:

We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-

\mu_{\hat{p}}=p

\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}

, where p=population proportion and n= sample size.

Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.

i.e. p= 19%=0.19

The for sample size n= 25

The mean and the standard error of the sampling distribution of the sample proportions will be :-

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=\sqrt{\dfrac{0.19(1-0.19)}{25}}\\\\=\sqrt{0.006156}=0.0784601809837\approx0.0785

Hence , the mean and the standard error of the sampling distribution of the sample proportions :

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=0.0785

8 0
4 years ago
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