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4 years ago

Can someone help me

Mathematics

1 answer:

jeka57 [31]4 years ago

8 0

Number one is really easy just set it up in proportions. 420 over x and 7 hours over 24 cause you know there 24 hours in a day and then cross division and simplify. I think.

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If C(x) is the cost of producing x units of a commodity, then the average cost per unit is c(x) = C(x)/x. Consider the cost func

nadya68 [22]

Answer:

a) C(1,000)=288,491.11 $

b) c(1,000)=288.49 $/u

c) dC/dx(1,000)=349.74 $/u

d) x=100 u

e) c=220 $/u

Step-by-step explanation:

(a) Find the total cost at a production level of 1000 units.

$C(x) = 2,000 + 160x + 4x^{3/2}\\\\C(1,000)=2,000 + 160(1,000) + 4(1,000)^{3/2}\\\\C(1,000)=2,000+160,000+126,491.11= 288,491.11$

(b) Find the average cost at a production level of 1000 units.

$c(x)=C(x)/x\\\\c(1,000)=C(1,000)/1,000=288,491.11/1,000=288.49$

$\frac{dC}{dx} =0+160+4*(3/2)x^{3/2-1}=160+6x^{1/2}\\\\dC/dx|_{1,000}=160+6*(1,000)^{1/2}=160+189.74=349.74$

(d) Find the production level that will minimize the average cost.

$c=2,000x^{-1}+160+4x^{1/2}\\\\dc/dx=2,000(-1)x^{-2}+0+4(1/2)x^{-1/2}=0\\\\-2,000x^{-2}+2x^{-1/2}=0\\\\2x^{-1/2}=2,000x^{-2}\\\\x^{-1/2+2}=1,000\\\\x^{3/2}=1,000\\\\x=1,000^{2/3}=100$

(e) What is the minimum average cost?

$c(x) = 2,000/x + 160 + 4x^{1/2}\\\\C(100)=2,000/100 + 160 + 4(100)^{1/2}=20+160+40=220$

5 0

3 years ago

The graph above is the graph of: y = | x + 4 | − 2 y = | x − 4 | − 2 y = | x − 2 | − 4

Liono4ka [1.6K]

We need to identify the equation of the graph given.

This graph corresponds to a translation of the graph described as:

$y=|x|$

Comparing the graph given with the one above, we can see it was shifted 4 units to the left.

When we translate the graph of a function f(x) d units to the left, it is transformed as:

$f(x)\rightarrow f(x+d)$

4 0

1 year ago

In Death Valley, California, the highest ground temperature recorded was 94°C on July 15, 1972. In the formula C= 5/9 (F - 32) ,

gulaghasi [49]

Answer:

$F=201.2\°$

Step-by-step explanation:

we know that

$\°C=\frac{5}{9}[\°F-32]$

For $C=94\°$

substitute in the formula and solve for F

$94=\frac{5}{9}[F-32]$

$(\frac{9}{5})*94=[F-32]$

$F=(\frac{9}{5})*94+32$

$F=201.2\°$

8 0

3 years ago

Use a protractor to find the measure of the largest angle in the figure. Write it in degrees.

Svetradugi [14.3K]

What you can put is an obtuse 108 degrees
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5 0

4 years ago

The surface area of a right cone is 400.2 m2. The radius of the cone is 6.0 m. Determine the height of the cone to the nearest m

svetoff [14.1K]

S = πr(r + √(h² + r²))
  400.2 = 3.14(6)(6 + √(h² + 6²))
  400.2 = 18.84(6 + √(h² + 36))
  18.84   18.84
  21¹⁰⁹/₄₇₁ = 6 + √(h² + 36))
  - 6 - 6
  15¹⁰⁹/₄₇₁ = √(h² + 36)
231²²¹⁰⁰⁵/₂₂₁₈₄₁ = h² + 36
- 36   - 36
195²²¹⁰⁰⁵/₂₂₁₈₄₁ = h²
  14 ≈ h

8 0

3 years ago