\left[x _{4}\right] = \left[ \frac{ - \left( -1\right) ^{\frac{3}{4}}\,\sqrt[4]{\left( 20 - 21\,z^{2}\right) }}{\sqrt[4]{4}}\right][x4]=[4√4−(−1)434√(20−21z2)]
I hope helping with u
Answer:
The answer for part B is I think 92 and 92. And for part A she could get 97 and 97 as the test average would be 92.
Step-by-step explanation:
I kinda explained it in the answer yeah but I hope that helps.
Answer:
no solution
Step-by-step explanation:
2x-5=8x+7-6x
2x-5=2x+7
-5=7
Not true so no solution
Answer:


Step-by-step explanation:
We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-


, where p=population proportion and n= sample size.
Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.
i.e. p= 19%=0.19
The for sample size n= 25
The mean and the standard error of the sampling distribution of the sample proportions will be :-


Hence , the mean and the standard error of the sampling distribution of the sample proportions :

