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Leokris [45]
4 years ago
11

For the sequence given recursively by ak = 2ak-1 - 3 for k > 2, where a1 = 4, someone has guessed a closed form and used the

predicate R(n) for the statement "an = 2^n-1 +3." an = 23. ORO S (a) Are R(1), R(2), R(3), and R(4) true?
Mathematics
1 answer:
den301095 [7]4 years ago
6 0

Answer:

True

Step-by-step explanation:

Given that recurrence formula is

a_k = 2a_{k-1} -3\\,k>2\\ and

a_1 =4

From this we can find

a_2 = 2a_1-3\\= 8-3 =5\\a_3 =2(5)-3 =7\\a_4 = 2(7)-3 = 11\\

Let us check now R's for these numbers

R(1) is trivially true

R(2) = 2^{2-1} +3 =5\\R(3) = 2^{3-1} +3 =7\\R(4) = 2^{4-1} +3 =11

We find that these matches with a values we found using recurrence formula

Hence we can say that R(1), R(2), R(3), and R(4) are true

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