84 pounds of Type B coffee is used
<em><u>Solution:</u></em>
Let "x" be the pounds of type A coffee
Let "y" be the pounds of type B coffee
Cost per pound of type A = $ 5.50
Cost per pound of Type B = $ 4.20
<em><u>This month, Chau made 143 pounds of the blend</u></em>
x + y = 143
x = 143 - y -------- eqn 1
<em><u>For a total cost of $677.30. Thus we frame a equation as:</u></em>
pounds of type A coffee x Cost per pound of type A + pounds of type B coffee x Cost per pound of Type B = 677.30

<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 1 in eqn 2</u></em>

Thus 84 pounds of Type B coffee is used
Answer:
92 92 238
Step-by-step explanation: 92 because a proton and electron have the same and first is 92 and well 238
Answer : The correct option is 
Step-by-step explanation :
According to the BODMAS rule, when the expression contains brackets open ((), {}, []) we have to first simplify the bracket followed by of (powers and roots etc.) and then we have to solve the division, multiplication, addition and subtraction from left to right order (respectively).
The given expression is:
![[\frac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}]^{-1}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%7B%283a%5E5b%29%5E%7B-2%7D%7D%5D%5E%7B-1%7D)
![=[\frac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}]^{1}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B%283a%5E5b%29%5E%7B-2%7D%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D%5E%7B1%7D)
![=[\frac{1}{(3a^5b)^{2}}\times \frac{1}{(2a^{-3}b^4)^2}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B%283a%5E5b%29%5E%7B2%7D%7D%5Ctimes%20%5Cfrac%7B1%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{1}{4a^{-6}b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7B1%7D%7B4a%5E%7B-6%7Db%5E8%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{a^6}{4b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7Ba%5E6%7D%7B4b%5E8%7D%5D)

Thus, the given expression is equivalent to 
Answer:

Step-by-step explanation:
We are given that
Volume of cylinder =
Height of cylinder=9 cm
We have to find the area of base of the pillar.
We know that
Volume of cylindrical pillar=
Where Base=
Substitute the values then we get


Hence, the area of base of the pillar=